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disa [49]
3 years ago
7

A scuba diver is practicing in a marked pool. He begins 3 feet below the surface of the water and then dives down to the 9 foot

marker. How far did he dive?
Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

x+3=9

I believe he dove 6 feet because started 3 feet below water and went down to 9 feet below water and the difference between 9 feet and 3 feet is 6 feet.

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The point P(x,y) lies on the terminal side of an angle θ = -60° in standard posistion. What are the signs of the values of x and
lyudmila [28]

Answer:

x positive, y negative

Step-by-step explanation:

-60 is the 4th quadrant of the unit circle ( negative angles go clockwise from 0), so  the x value is positive and the y value is negative.

3 0
4 years ago
Drag a description to match each equation.
AnnZ [28]

Given:

The descriptions and equations. The equations are

y=4x

y=x+4

To find:

The correct description for each equation and match them.

Solution:

We know that, "+" is used for more and "×" is used for times.

Additive: y is 4 more than x.

y=x+4

Additive: x is 4 more than y.

x=y+4

Multiplicative: y is 4 times x.

y=4x

Multiplicative: x is 4 times y

x=4y

Therefore, the correct description for the equation y=4x is "Multiplicative: y is 4 times x " and the correct description for the equation y=x+4 is "Additive: y is 4 more than x. "

4 0
3 years ago
The perimeter of a rectangular e room is 24 feet. Twice the length
andrey2020 [161]

Answer:

i am gessing to divide

Step-by-step explanation:

3 0
3 years ago
Which is the equation of a line perpendicular to the line with the equation:<br>y = 1/4x + 2​
Wittaler [7]

Answer:

4x + y = k

Step-by-step explanation:

=> 4y = x + 8

=> x - 4y = -8

Slope = 1/4

The other line's slope = -4

4x + y = k is the answer.

4 0
3 years ago
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. find the width and length.
maksim [4K]

Answer:

Width=6.5 cm

Length=12 cm

Step-by-step explanation:

Step 1: Express the lengths and widths

Width=w

Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1

Step 2: Solve for the length and width

A=L×W

where;

A=area of the photograph

L=length of the photograph

W=width of the photograph

In our case;

A=91 cm²

L=2 w-1

W=w

91=(2 w-1)w

2 w²-w=91

2 w²-w-91=0, is a quadratic equation

solve for w

w={-1±√(-1²-4×2×-91)}/(2×2)

w=(-1±27)/4

w=(27-1)/4=6.5, or (-1-27)/4=-8

Take w=6.5 cm

L=(2×6.5)-1=13-1=12 cm

Width=6.5 cm

Length=12 cm

6 0
3 years ago
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