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Misha Larkins [42]
3 years ago
8

CAN YOU TELL ME ANSWER OF THIS QUESTION...WITH STEPS...THANKS

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

0.2416472823

Step-by-step explanation:

1.23×0.6975=

0.857925

0.857925/60.8=0.0141106086

3√0.0141106086

=0.2416472823

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Lindsay​ Electronics, a small manufacturer of electronic research​ equipment, has approximately 6 comma 500 items in its invento
masya89 [10]

Answer:

The total number of items to be counted each day ≈ 100

Step-by-step explanation:

Lindsay​ Electronics has 6,500 items in its inventory.

11​% of the items in inventory are A​ items

33% of the items in inventory are B items

56​% of the items in inventory are C items

A items are counted every 20 working​ days

B items are counted every 62 working​ days

C items are counted every 121 working​ days

How many items need to be counted each​ day?

First we will find the number of items of type A, B and C

Number of A​ items = 11​% of 6,500 = 0.11*6500 = 715

Number of B items = 33% of 6,500 = 0.33*6500 = 2145

Number of C items = 56% of 6,500 = 0.56*6500 = 3640

The number of A items to be counted each day is

A items = 715/20

The number of B items to be counted each day is

B items = 2145/62

The number of C items to be counted each day is

C items = 3640/121

The total number of items to be counted each day is

Total items = 715/20 + 2145/62 + 3640/121

Total items = 100.42

Rounding the answer to the nearest whole number yields,

Total items ≈ 100

3 0
4 years ago
-2x+3-4x^2+11-15x+2x^2-15=?
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Answer:

-2x^{2} -17x-1

Step-by-step explanation:

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3 years ago
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77julia77 [94]
Simplify 9 /12 and we get:
3/4 
which is the same.
6 0
3 years ago
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faust18 [17]

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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