The shorter side of the triangle is 18 cm and each of the longer sides are 54 cm
<u>Solution:</u>
Given that triangle has perimeter of 126 cm
Let the length of the shorter side of the triangle be "a"
The 2 longer sides are 3 times as long as the shortest side
So length of 2 longer sides = 3(length of the shorter side)
length of 2 longer sides = 3a
<em><u>The perimeter of triangle is given as:</u></em>
perimeter of triangle = length of the shorter side + length of 2 longer sides
perimeter of triangle = a + 3a + 3a
126 = a + 3a + 3a
7a = 126
a = 18
So length of shorter side = 18 cm
length of 2 longer sides are each = 3a = 3(18) = 54 cm
Thus, the shorter side of the triangle is 18 cm and each of the longer sides is 54 cm
I would probably say (0,0) just because (5,0) falls on the x-axis and not on the y-axis and the other are just regular plotting coordinates. (0,0) is the only one that falls on the y-axis although it still falls on the x-axis as well
Answer:263 square units
Step-by-step explanation:
No work needed
Answer:
10.75
Step-by-step explanation:
The cost of an adult ticket is £6 more than that of a child ticket, so will be shown by c+6.
Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
so, a childs ticket is 4.75
now to find the cost of an adult ticket you add 6,
4.75 + 6
= 10.75
This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.
Area of a rectangle:
The area of rectangle of length l and width w is given by:
w(2w + 3) = 9
From this, we get that:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this question:
Thus a quadratic equation with 
Then
Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.
Another similar problem can be found at brainly.com/question/16995958
