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Oduvanchick [21]
3 years ago
6

Solve for x:

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

2<x<3

Step-by-step explanation:

4x-4<8 AND 9x+5>23

Solve the first inequality

4x-4<8

Add 4 to each side

4x-4+4 <8+4

4x<12

Divide by 4

4x/4 <12/4

x <3

Solve the second inequality

9x+5>23

Subtract 5 from each side

9x+5-5>23-5

9x >18

Divide by 9

9x/9>18/9

x>2

Put together

x<3 and x>2

2<x<3

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Step-by-step explanation:

slope= -4/3

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y=mx+b

y= -4/3x-4

4 0
3 years ago
What is 0.25 as a percentage
Varvara68 [4.7K]

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25%

Step-by-step explanation:

7 0
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What is the final answer for 6x-6-7x=-13/2
olya-2409 [2.1K]
6x - 6 - 7x = -13/2

Multiply both sides by 2:
12x - 12 - 14x = -13

Simplify:
-2x - 12 = -13

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6 0
3 years ago
Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05
exis [7]

we are given

f(x)=\frac{x^2-5x}{x^2-x-20}

Firstly, we will simplify it

f(x)=\frac{x(x-5)}{(x-5)(x+4)}

f(x)=\frac{x}{(x+4)}

At x=5.5:

we can plug x=5.5

f(5.5)=\frac{5.5}{(5.5+4)}

f(5.5)=0.578947

At x=5.1:

we can plug x=5.1

f(5.1)=\frac{5.1}{(5.1+4)}

f(5.1)=0.56043956

At x=5.05:

we can plug x=5.05

f(5.05)=\frac{5.05}{(5.05+4)}

f(5.05)=0.558011

At x=5.01:

we can plug x=5.01

f(5.01)=\frac{5.01}{(5.01+4)}

f(5.01)=0.5560488

At x=5.005:

we can plug x=5.005

f(5.005)=\frac{5.005}{(5.005+4)}

f(5.005)=0.5558023

At x=5.001:

we can plug x=5.001

f(5.001)=\frac{5.001}{(5.001+4)}

f(5.001)=0.5556049

At x=4.9:

we can plug x=4.9

f(4.9)=\frac{4.9}{(4.9+4)}

f(4.9)=0.5505617

At x=4.95:

we can plug x=4.95

f(4.95)=\frac{4.95}{(4.95+4)}

f(4.95)=0.5530726

At x=4.99:

we can plug x=4.99

f(4.99)=\frac{4.99}{(4.99+4)}

f(4.99)=0.55506117

At x=4.995:

we can plug x=4.995

f(4.995)=\frac{4.995}{(4.995+4)}

f(4.995)=0.55503085

At x=4.999:

we can plug x=4.999

f(4.999)=\frac{4.999}{(4.999+4)}

f(4.999)=0.55550616



7 0
4 years ago
Help me please. Thank you in advance ​
Dmitriy789 [7]
Your answer is going to be roughly 9.3327
3 0
3 years ago
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