Answer:
None of the above
Explanation:
To find the type of lines they create, first find the slope of the equations.(Change form to y intercept)
4x-2y=-5
-2y=-4x-5
y=2x+(5/2)
Slope=2
-2x+3y=-3
3y=2x-3
y=(2/3)x-1
Slope=2/3
So, one has slope=2 and the other has slope=2/3. They’re not parallel because slopes are not the same. They’re not perpendicular because the slopes are not opposites. They’re not equal because their equations are not the same. So, none of the above.
Hey There!
The answer to your problem is 
or 
both answers are correct!
<u>Step 1: Subtract x²+12 from both sides.</u>
−7x−(x²+12)=x²+12−(x²+12)
−x²−7x−12=0
<u>Step 2: Factor left side of equation.</u>
<u>Step 3: Set factors equal to 0.</u>
or 
<u>Get your answer:</u>
or
Answer: ∠ABE=20°
Step-by-step explanation:
∵ AB=BC
∴ ΔABC is a isosceles triangle
∵ ∠A=30
∴ ∠C=30
∵ The interior angle sum of triangle is 180°
∵ ∠A+∠B+∠C=180
30+∠B+30=180
∠B+60=180
∠B=120 (∠ABC)
∵ ∠EBD+∠ABE+∠ABC=linear pair
∴∠EBD+∠ABE+∠ABC=180°
4x+2x+120=180
6x+120=180
6x=60
x=10
∠ABE=2x=2(10)=20°
Hope this helps!! :)
Please let me know if you have any question
Answer:
Therefore, x is 1 and 2.
Step-by-step explanation:
As you plot both equations on the same graph, you will get something like this, shown in the graph.
Then, you have to find the x solutions where they intersect.
So, both equations intersect at x = 1 and 2.
