Question

Help me plsss!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Answer:

C.Infinitely many solutions

I solved by substitution

$2x+3y=12\\-3y-3y\\2x=-3y+12\\\frac{2x=-3y+12}{2} \\x=-\frac{3}{2} y+6$$-6y=4x-24\\-6y=4(-\frac{3}{2} y+6)-24\\-6y=-6y\\-6y+6y=-6y+6y\\0=0$Infinitely many solutions

Answer 2

It can be both A and B so i think the answer is C.... hope this helps