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3 years ago

What’s the answer to this question?

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

4 0

Answer:

#3 is not a function

Step-by-step explanation:

One input only has one output.

but #3, input (3) has 2 outputs (4 and 6)

#3 is not a function

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ava bought 6 packages of tulip bulbs and 12 bags of dafodill bulbs for a total of $198 grace spent $254 buying 14 packages of tu

sasho [114]

Answer:

Answer:

Step-by-step explanation:

Let x represent the cost of one package of tulip bulbs.

Let y represent the cost of one bag of daffodil bulbs.

Ava bought 6 packages of tulip bulbs and 12 bags of daffodil bulbs for a total of $198. This means that

6x + 12y = 198- - - - - - - - - - - - -1

Grace spent $254 buying 14 packages of tulip bulbs and 12 bags of daffodil bulbs. This means that

14x + 12y = 254- - - - - - - - - - - - 2

Subtracting equation 2 from equation 1, it becomes

- 8x = - 56

x = - 56/-8

x = 7

Substituting x = 7 into equation 1, it becomes

6 × 7 + 12y = 198

42 + 12y = 198

12y = 198 - 42

12y = 156

y = 156/12

y = 13

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Step-by-step explanation:

Answer:

Step-by-step explanation:

Let x represent the cost of one package of tulip bulbs.

Let y represent the cost of one bag of daffodil bulbs.

Ava bought 6 packages of tulip bulbs and 12 bags of daffodil bulbs for a total of $198. This means that

6x + 12y = 198- - - - - - - - - - - - -1

Grace spent $254 buying 14 packages of tulip bulbs and 12 bags of daffodil bulbs. This means that

14x + 12y = 254- - - - - - - - - - - - 2

Subtracting equation 2 from equation 1, it becomes

- 8x = - 56

x = - 56/-8

x = 7

Substituting x = 7 into equation 1, it becomes

6 × 7 + 12y = 198

42 + 12y = 198

12y = 198 - 42

12y = 156

y = 156/12

y = 13

answers left

Answers are unlimited right now

Unlock all verified answers

Grow with a massive community of home learners

Ask your own homework questions

+98

douwdek0 and 98 others just joined Brainly

JOIN FOR FREE

Click to let others know, how helpful is it

0.0

0 votes

THANKS

Comments Report

Read more on Brainly.com - brainly.com/question/15268568#readmore

8 0

3 years ago

2800 to 2100 percent of change

Gennadij [26K]

2800-2100=700
2800/700=4
4% decrease

7 0

3 years ago

Which graph shows the correct solution to the linear-quadratic system of inequalities below?

LUCKY_DIMON [66]

Answer:

(the pic)

Step-by-step explanation:

I used a link

8 0

3 years ago

Read 2 more answers

A company wishes to manufacture some boxes out of card. The boxes will have 6 sides (i.e. they covered at the top). They wish th

Serhud [2]

Answer:

The dimensions are, base $b=\sqrt[3]{200}$ , depth $d=\sqrt[3]{200}$ and height $h=\sqrt[3]{200}$ .

Step-by-step explanation:

First we have to understand the problem, we have a box of unknown dimensions (base $b$ , depth $d$ and height $h$ ), and we want to optimize the used material in the box. We know the volume $V$ we want, how we want to optimize the card used in the box we need to minimize the Area $A$ of the box.

The equations are then, for Volume

$V=200cm^3 = b.h.d$

For Area

$A=2.b.h+2.d.h+2.b.d$

From the Volume equation we clear the variable $b$ to get,

$b=\frac{200}{d.h}$

And we replace this value into the Area equation to get,

$A=2.(\frac{200}{d.h} ).h+2.d.h+2.(\frac{200}{d.h} ).d$

$A=2.(\frac{200}{d} )+2.d.h+2.(\frac{200}{h} )$

So, we have our function $f(x,y)=A(d,h)$ , which we have to minimize. We apply the first partial derivative and equalize to zero to know the optimum point of the function, getting

$\frac{\partial A}{\partial d} =-\frac{400}{d^2}+2h=0$

$\frac{\partial A}{\partial h} =-\frac{400}{h^2}+2d=0$

After solving the system of equations, we get that the optimum point value is $d=\sqrt[3]{200}$ and $h=\sqrt[3]{200}$ , replacing this values into the equation of variable $b$ we get $b=\sqrt[3]{200}$ .

Now, we have to check with the hessian matrix if the value is a minimum,

The hessian matrix is defined as,

$H=\left[\begin{array}{ccc}\frac{\partial^2 A}{\partial d^2} &\frac{\partial^2 A}{\partial d \partial h}\\\frac{\partial^2 A}{\partial h \partial d}&\frac{\partial^2 A}{\partial p^2}\end{array}\right]$

we know that,

$\frac{\partial^2 A}{\partial d^2}=\frac{\partial}{\partial d}(-\frac{400}{d^2}+2h )=\frac{800}{d^3}$

$\frac{\partial^2 A}{\partial h^2}=\frac{\partial}{\partial h}(-\frac{400}{h^2}+2d )=\frac{800}{h^3}$

$\frac{\partial^2 A}{\partial d \partial h}=\frac{\partial^2 A}{\partial h \partial d}=\frac{\partial}{\partial h}(-\frac{400}{d^2}+2h )=2$

Then, our matrix is

$H=\left[\begin{array}{ccc}4&2\\2&4\end{array}\right]$

Now, we found the eigenvalues of the matrix as follow

$det(H-\lambda I)=det(\left[\begin{array}{ccc}4-\lambda&2\\2&4-\lambda\end{array}\right] )=(4-\lambda)^2-4=0$

Solving for $\lambda$ , we get that the eigenvalues are: $\lambda_1=2$ and $\lambda_2=6$ , how both are positive the Hessian matrix is positive definite which means that the function $A(d,h)$ is minimum at that point.

4 0

3 years ago

Need help ASAP! I don’t understand this please help

lana [24]

Answer:

Already answered.

Step-by-step explanation:

brainly.com/question/16954459

7 0

3 years ago