All categories

3 years ago

The length of 12cm and 5 cm missing one

Mathematics

1 answer:

alisha [4.7K]3 years ago

5 0

Answer:

13cm

Step-by-step explanation:

Let the given lengths be the opposte amd adjacent sides of a right triangle'

The missing side will be the hypotenuse

Using the pythagoras theorem;

hyp^2 = 5² + 12²

hyp² = 25 + 144

hyp² = 169

hyp =√169

hyp = 13cm

Hence the missing one is 13cm

You might be interested in

Use integration by parts to find the integrals in Exercise.<br> ∫^3_0 3-x/3e^x dx.

Viefleur [7K]

Answer:

8.733046.

Step-by-step explanation:

We have been given a definite integral $\int _0^3\:3-\frac{x}{3e^x}dx$ . We are asked to find the value of the given integral using integration by parts.

Using sum rule of integrals, we will get:

$\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx$

We will use Integration by parts formula to solve our given problem.

$\int\ vdv=uv-\int\ vdu$

Let $u=x$ and $v'=\frac{1}{e^x}$ .

Now, we need to find du and v using these values as shown below:

$\frac{du}{dx}=\frac{d}{dx}(x)$

$\frac{du}{dx}=1$

$du=1dx$

$du=dx$

$v'=\frac{1}{e^x}$

$v=-\frac{1}{e^x}$

Substituting our given values in integration by parts formula, we will get:

$\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(x*(-\frac{1}{e^x})-\int _0^3(-\frac{1}{e^x})dx)$

$\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))$

$\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx=3x-\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))$

Compute the boundaries:

$3(3)-\frac{1}{3}(-\frac{3}{e^3}- (\frac{1}{e^3}))=9+\frac{4}{3e^3}=9.06638$

$3(0)-\frac{1}{3}(-\frac{0}{e^0}- (\frac{1}{e^0}))=0-(-\frac{1}{3})=\frac{1}{3}$

$9.06638-\frac{1}{3}=8.733046$

Therefore, the value of the given integral would be 8.733046.

6 0

2 years ago

Can you help me with this question i dont get it

Marizza181 [45]

The answer is c or A

3 0

3 years ago

Read 2 more answers

What is 1/2 X (6 X 4)+3 + 2 Please show your work

exis [7]

Answer:

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

$\dfrac{1}{2}\times\underbrace{(6\times4)}_{1}+3+2\\\\=\underbrace{\dfrac{1}{2}\times24}_{2}+3+2\\\\=12+3+2=17$

4 0

2 years ago

Find f(-3) for f(x) = 4(2)^x<br> A. 1/8<br> B. -32<br> C. 1/2<br> D. -24

Law Incorporation [45]

${{\boxed{{\tt{\color{blue}{✎A\color{red}{n\color{green}{s\color{lime}{w\color{skyblue}{e\color{cyan}{r\color{blue}{\color{purple}{}}}}}}}}}}}}}$

Find f(-3) for f(x) = 4(2)^x

D.-24

((−3)(4))(2)

=(−12)(2)

=−24

8 0

2 years ago

Please help with this fast

Elena-2011 [213]

Answer:

Part 1) The value of x is 50°

Part 2) The measure of angle LOK is 114°

Option C

Step-by-step explanation:

we know that

if two angles are supplementary, then their sum is equal to 180 degrees

(x+64)°+66°=180°

solve for x

x+130°=180°

x=180°-130°=50°

Find the measure of angle LOK

∠LOK=(x+64)°

∠LOK=(50+64)°=114°

4 0

2 years ago