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sasho [114]
3 years ago
11

What is 5.3 times 9.7 pls help me

Mathematics
2 answers:
Nitella [24]3 years ago
7 0

Answer:

Step-by-step explanation:

 5.3

<u>x 9.7</u>

 371

<u>4770</u>

51.41

Korolek [52]3 years ago
3 0

the answer is

51.41

hope that help

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Which is greater: 75,409 – 6,000=69,409 or 29,300 + 40,109=69,409.
natali 33 [55]
Neither there the same
6 0
3 years ago
Read 2 more answers
Line AB has endpoints A(-4,5) and B(3,5). What is the x-coordinate of a point C such that B is the midpoint of line AC
Ipatiy [6.2K]
Easy peasy

the midpoint between (x_1,y_1) and (x_2,y_2) is
(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})
just average them

so given that (3,5) is the midpoint of (-4,5) and (x,y)
(\frac{-4+x}{2},\frac{5+y}{2})=(3,5)
so by logic
\frac{-4+x}{2}=3 and \frac{5+y}{2}=5
times both sides by 2 for everybody
-4+x=6 and 5+y=10
add 4 to both sides for left one and minus 5 from both sides for right
x=10 and y=5

the coordinate of point C is (10,5)
the x coordinate is 10
7 0
3 years ago
Evaluate the expression. 2x – 19, when x = –11 3 –41 –3 41
kakasveta [241]
Substitute (-11) in for x. You will get 2(-11)-19. Then, use the order of operations to get -22-19=
-41.
Hope that helps!
3 0
3 years ago
17. Suppose U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} is the universal set, and P = {1, 4, 9}. What is P’?
Lostsunrise [7]
The correct answer is as follows
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7 0
3 years ago
A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

           x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

4 0
3 years ago
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