Question

I WILL GIVE MORE POINTS IF I GET THE RIGHT ANSWER

Answer 1

Answer:

v= 6km/h - 1km/h^2 * t

Step-by-step explanation:

From the information, it seems the runner is slowing down because the speed at 1st hour is 5km/h but at 3rd hour becomes 3km/h.

If v= velocity, v0= initial speed, t= time, and the a=acceleration then the function would be:  

v= v0 + a * t

To find the acceleration you need to do this equation:

acceleration= velocity1- velocity3 / t3-t1

a = (3km/h-5km/h)/ (3 hour- 1 hour)

a = (-2km/h)/2hour= -1 km/hour^2

After that, you need to find the initial speed. Try to put the 1st-hour variable into the full equation. It would look like this

v= v0 + a * t

5km/h= v0 + (-1 km/hour^2 * 1 hour)

v0= 5km/h + 1km/h

v0= 6km/h  

Then the full function would be:

v= 6km/h - 1km/h^2 * t

The graph would look like a backslash(\) from 5 gradually go down to 1.  

6                          

5 O                    

4      O                

3          O              

2              O            

1                   O      

   1   2  3  4  5