The equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3
<h3>How to find the equation of a line?</h3>
The equation of a line in slope-intercept form is expressed as y = mx + b
where
m is the slope
b is the y-intercept
Given the coordinate points (-2, 4) and (10, 0)
Find the slope
Slope = -4/12
Slope = -1/3
Determine the y-intecept
0 = -1/3(10) + b
b = 10/3
Determine the equation
y = -1/3x + 10/3
Hence the equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3
Learn more on equation of a line here: brainly.com/question/13763238
Answer:
-16
Step-by-step explanation:
-k² -(3k-5n)+4n k=-1 , n= -2
= -(-1)² - ( 3(-1) -5(-2) )+4(-2)
= -1-(-3+10)-8
= -1-(7)-8
= -1-7-8
= -16
Answer:
Hope this helps
Step-by-step explanation:
j=14
Answer: Just put the numbers of the x and y coordinates onto the graph and draw a line.
Step-by-step explanation:
Uh I'm not sure how to graph online but just do that and your teacher should be good with it!
