All categories

2 years ago

Evaluate the following expression for x=-2 -4x+8+2x+3

Mathematics

1 answer:

sergiy2304 [10]2 years ago

8 0

Answer:

Step-by-step explanation:

x = 2

-4x+8+2x+3 = ?

-4 (-2) + 8 + 2 (-2) + 3 =

= 8 + 8 - 4 + 3

= 16 - 4 + 3

= 12 + 3

= 15

hopefully this helped you :)

You might be interested in

Ben dove to a depth of 500 feet. Sabrina dove to a depth of 250 feet. Which diver is at the higher elevation?

Serhud [2]

Answer:

Sabrina is at a higher elevation.

Step-by-step explanation:

She has dropped less than Ben, so she is higher up.

5 0

2 years ago

12x-4x+3+11 help me solve this problem

daser333 [38]

Answer:

8x + 14

Step-by-step explanation:

12x - 4x + 3 + 11 (Subtract 12x - 4x)

8x + 3 + 11 (Add 3 + 11)

8x + 14

Tip: the like-terms 12x and 4x can be subtracted like regular numbers because they have the same variable and exponent.

6 0

2 years ago

I need help with 5 and 7

Thepotemich [5.8K]

I can't see them all the way

3 0

2 years ago

Mikaela placed a frame around a print that measures 10 inches by 10 inches. The area of just the frame itself is 69 square inche

olchik [2.2K]

Answer:

1.5 in

Step-by-step explanation:

Let x be the width of the frame.

Side of print=10 in

Area of frame=69 square in

We have to find the width of the frame.

Side of frame=10+x+x=10+2x

Area of square= $(side)^2$

By using the formula

Area of print= $10\times 10=100in^2$

Area of frame with print= $(10+2x)^2$

Area of frame=Area of frame with print-Area of print

$69=(10+2x)^2-100$

$(10+2x)^2=69+100=169$

$(10+2x)=\sqrt{169}=\pm 13$

$10+2x=13$

Because Side is always positive.

$2x=13-10=3$

$x=\frac{3}{2}=1.5$

Hence, width of frame=1.5 in

3 0

2 years ago

A circle representing a pool is graphed with a center at the origin. Grant enters the pool at point A and swims over to a friend

MA_775_DIABLO [31]

From the diagram above you can see that points A and B have coordinates (8,0) and (-4,6), respectively.

The equation of the line passing through the pointa A and B is:

$y-y_A=\dfrac{y_B-y_A}{x_B-x_A}(x-x_A).$

Then

$y-0=\dfrac{6-0}{-4-8}(x-8),\\ \\y=-\dfrac{6}{12}(x-8),\\ \\y=-\dfrac{1}{2}(x-8),\\ \\y=-\dfrac{1}{2}x+4.$

Answer: $y=4-\dfrac{1}{2}x.$

8 0

2 years ago

Read 2 more answers