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3 years ago

I need help with this, it's due in 15 mins-

Mathematics

1 answer:

LiRa [457]3 years ago

3 0

Answer:

Mean: 3.5263157894737

Median: 3

Mode: 3

Step-by-step explanation: The mode is 3 because the mode is for which number pops up the most, which is 3.

I got the median by crossing out 8 from the left and the right of the number set and got 3 as the last number.

I got the mean by adding up all the numbers and divided it by the amount of numbers in the set.

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Q 1.) Expand using identities: i. (a+2b)² ii. (5x-3y)² iii. (3a+4)(3a-4)(9a²+16)

Ganezh [65]

Step-by-step explanation:

#1.

(a + 2b)²

Using identity (x + y)² = x² + 2xy + y², we get:

= (a)² + (2b)² + 2 × (a) × (2b)

= a² + 4b² + 4ab

= a² + 4ab + 4b² Ans.

#2.

(5x - 3y)²

Using identity (a - b)² = a² - 2ab + b², we get:

= (5x)² + (3y)² - 2 × (5x) × (3y)

= 25x² + 9y² - 30xy

= 25x² - 30xy + 9y² Ans.

#3.

(3a + 4)(3a - 4)(9a² + 16)

Using identity (x + y)(x - y) = x² - y², we get:

= [(3a)² - (4)²][9a² + 16]

= (9a² - 16)(9a² + 16)

= (9a²)² - (16)²

= 81a⁴ - 256 Ans.

4 0

3 years ago

A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Sheila scoops out a bowl full of nuts and counts how

Zanzabum

Assuming that the ratios stay the same, the answer is going to be 6 because the total number of nuts drawn originally was 48, and 9 were cashews. To maintain this ratio when 32 nuts were drawn, the number of cashews will be 6.

6 0

3 years ago

Liz has a 24 inch ribbon she cuts nine 2 inch pieces from her original ribbon. how much of the original ribbon is left?

Tpy6a [65]

6 inches from the original piece of ribbon is left.

4 0

3 years ago

Use differentials to estimate the amount of paint needed (in m3) to apply a coat of paint 0.04 cm thick to a hemispherical dome

pogonyaev

The amount of paint is the volume of paint needed.

The amount of paint needed is 0.065312 cubic meters

<h3>How to determine the amount of paint needed</h3>

The volume of a hemisphere is:

$V = \frac 23\pi r^3$

Differentiate the above equation

$V' = 2\pi r^2 r'$

The above equation represents the estimate of the amount of paint needed.

Where:

r represents the radius (r = 52/2 m)
r' represents the thickness (r' = 0.04 cm)

So, we have:

$V' = 2\pi r^2 r'$

$V' = 2 * 3.14 * (52/2\ m)^2 * (0.04cm)$

$V' = 2 * 3.14 * (26\ m)^2 * (0.04cm)$

Express cm as m

$V' = 2 * 3.14 * (26\ m)^2 * (0.0004m)$

$V' = 0.065312 m^3$

Hence, the amount of paint needed is 0.065312 cubic meters