Kim's method of sampling the students in the given scenario is said to; It is not a random survey.
<h3>What is a random sample?</h3>
Random sampling is defined as a sampling technique whereby each sample has an equal probability of being chosen. This means that a sample chosen randomly is meant to be an unbiased representation of the total population.
In this question, we are told that Kim asked the first 50 kids to school in the morning about a question and used their responses to arrive at a conclusion.
Now, Kim's method is not random because it is biased as only those who came earliest were asked.
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Answer:
to the fourth power, over 25 = 52 A… Get the answers you need, now! ... B. By simplifying 25 to 52 to make both powers base five and adding the exponents ... was used to simplify the expression is D. By finding the quotient of the ... rules of exponents simplify the expressions below: 2 4 3 0 4 6 4 -3 2 3 2.
Step-by-step explanation:
I would think A because regular quadrilaterals have 90-degree angles.
Answer:
See the proof below.
Step-by-step explanation:
Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."
Solution to the problem
For this case we can assume that we have N independent variables 
with the following distribution:
bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:
From the info given we know that 
We need to proof that 
by the definition of binomial random variable then we need to show that:
The deduction is based on the definition of independent random variables, we can do this:
And for the variance of Z we can do this:
![Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28Z%29_%20%3D%20E%28N%29%20Var%28X%29%20%2B%20Var%20%28N%29%20%5BE%28X%29%5D%5E2%20)
![Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5Bp%281-p%29%5D%20%2B%20Mq%281-q%29%20p%5E2)
And if we take common factor 
we got:
![Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5B%281-p%29%20%2B%20%281-q%29p%5D%3D%20Mpq%5B1-p%20%2Bp-pq%5D%3D%20Mpq%5B1-pq%5D)
And as we can see then we can conclude that
4a+2 because you divide 16a+8 by 4 because a square has 4 sides
