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Anastasy [175]
3 years ago
9

3.

Computers and Technology
1 answer:
jenyasd209 [6]3 years ago
3 0
Data label and pie slice
You might be interested in
When declaring the data type for a multidimensional array of strings, which statement would be most appropriate?
romanna [79]

Answer:

This question required option (See Explanation)

Explanation:

Required

How to declare 2D array

Using Java as a programming language of reference, the syntax to declare a 2D array is:

Data-Type [][] Array-Name = new Data-Type[Rows][Column]

From the question, the data type is String. So, the syntax becomes

String [][] Array-Name = new String[Rows][Column]

Assume the array name is: myArray; The above becomes

String [][] myArray= new String[Rows][Column]

<em>I will not assume values for Rows and Column, but it is worth saying that Rows and Columns are positive integers greater than 1 to make the array a 2 D array</em>

4 0
3 years ago
Systems management involves allocation of computer resources to keep all processes operating smoothly and at maximum efficiency.
olchik [2.2K]

Answer:operating system (OS), program that manages a computer's resources, especially the allocation of those resources among other programs. Typical resources include the central processing unit (CPU), computer memory, file storage, input/output (I/O) devices, and network connections.

Explanation:

8 0
3 years ago
Instructions
e-lub [12.9K]

Answer:

See explaination

Explanation:

dateType.h

#ifndef dateType_H

#define dateType_H

class dateType

{

public:

void setDate(int month, int day, int year);

//Function to set the date.

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day;

// dYear = year

int getDay() const;

//Function to return the day.

//Postcondition: The value of dDay is returned.

int getMonth() const;

//Function to return the month.

//Postcondition: The value of dMonth is returned.

int getYear() const;

//Function to return the year.

//Postcondition: The value of dYear is returned.

void printDate() const;

//Function to output the date in the form mm-dd-yyyy.

void isLeapYear() const;

dateType(int month = 1, int day = 1, int year = 1900);

//Constructor to set the date

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day; dYear = year;

// If no values are specified, the default

// values are used to initialize the member

// variables.

private:

int dMonth; //variable to store the month

int dDay; //variable to store the day

int dYear; //variable to store the year

};

#endif

dateType.cpp

#include <iostream>

#include "dateType.h"

using namespace std;

void dateType::setDate(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

int dateType::getDay() const

{

return dDay;

}

int dateType::getMonth() const

{

return dMonth;

}

int dateType::getYear() const

{

return dYear;

}

void dateType::printDate() const

{

cout << dMonth << "-" << dDay << "-" << dYear;

}

void dateType::isLeapYear() const

{

if ( dYear%400 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%100 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%4 == 0 )

cout<<endl<<dYear<< " is leap year.\n";

else

cout<<endl<<dYear<< " is not leap year.\n";

}

//Constructor with parameters

dateType::dateType(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

main.cpp

#include<iostream>

#include "dateType.h"

using namespace std;

int main()

{

dateType *dt1=new dateType();

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

dateType *dt2=new dateType(11,14,2019);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt2->setDate(13,32,2016);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt1->setDate(10,10,198);

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

system("pause");

return 0;

}

6 0
3 years ago
If there are three classes, Shape, Circle and Square, what is the most likely relationship among them?
xz_007 [3.2K]

Answer: B) Shape is a base class, and circle and square are derived classes of Shape.

Explanation:

Shape is a base class because circle and squares are the shapes so these are the derived class of the shape, which is inherited by the shape like circle and square. As, the base class (shape) is the class which are derived from the other classes like circle and square and it facilitates other class which can simplified the code re-usability that is inherited from the base class. Base class is also known as parent class and the super class.  

8 0
4 years ago
A proper divisor of a positive integer $n$ is a positive integer $d &lt; n$ such that $d$ divides $n$ evenly, or alternatively i
juin [17]

Answer:

The program written in Python is as follows:

<em>See Explanation section for line by line explanation</em>

for n in range(100,1000):

     isum = 0

     for d in range(1,n):

           if n%d == 0:

                 isum += d

     if isum == n * 2:

           print(n)

Explanation:

The program only considers 3 digit numbers. hence the range of n is from 100 to 999

for n in range(100,1000):

This line initializes sum to 0

     isum = 0

This line is an iteration that stands as the divisor

     for d in range(1,n):

This line checks if a number, d can evenly divide n

           if n%d == 0:

If yes, the sum is updated

                 isum += d

This line checks if the current number n is a double-perfect number

     if isum == n * 2:

If yes, n is printed

           print(n)

<em>When the program is run, the displayed output is 120 and 672</em>

4 0
3 years ago
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