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morpeh [17]
3 years ago
11

But this time use 16 kib pages instead of 4 kib pages. what would be some of the advantages of having a larger page size? what a

re some of the disadvantages?
Computers and Technology
1 answer:
uranmaximum [27]3 years ago
6 0

Here are the advantages and disadvantages of larger paper size: 

Advantages: 

Reduces minor page faults. 

Disadvantages: 

There will be a decrease in the number of frames. 

There will be an increase number of page faults. 

<span>Waste of more space with the internal fragmentation.</span>

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Do you play combat kite ?
nevsk [136]

Answer:

nah

Explanation:

7 0
3 years ago
How are the stop lamp bulbs connected in relation to each other? a. In parallel. b. In series. c. In series/parallel. d. None of
laiz [17]

In Parallel option A is true

Because In parallel circuit, the voltage across each components is same and the total current is sum of the currents through each component.

6 0
3 years ago
To reduce the number of used digital outputs of the microcontroller, the display board is connected to the main board through th
Luda [366]

Answer:

The program in Python is as follows:

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

num = input("Decimal: ")

BCDValue = ""

valid = True

for i in range(len(num)):

   if num[i].isdigit():

       if(int(num[i])>= 0 and int(num[i])<8):

           BCDValue += BCD[i]+" "

       else:

           valid = False

           break;

   else:

       valid = False

       break;

if(valid):

   print(BCDValue)

else:

   print("Invalid")

Explanation:

This initializes the BCD corresponding value of the decimal number to a list

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

This gets input for a decimal number

num = input("Decimal: ")

This initializes the required output (i.e. BCD value)  to an empty string

BCDValue = ""

This initializes valid input to True (Boolean)

valid = True

This iterates through the input string

for i in range(len(num)):

This checks if each character of the string is a number

   if num[i].isdigit():

If yes, it checks if the number ranges from 0 to 7 (inclusive)

       if(int(num[i])>= 0 and int(num[i])<8):

If yes, the corresponding BCD value is calculated

           BCDValue += BCD[i]+" "

       else:

If otherwise, then the input string is invalid and the loop is exited

<em>            valid = False</em>

<em>            break;</em>

If otherwise, then the input string is invalid and the loop is exited

<em>    else:</em>

<em>        valid = False</em>

<em>        break;</em>

If valid is True, then the BCD value is printed

<em>if(valid):</em>

<em>    print(BCDValue)</em>

If otherwise, it prints Invalid

<em>else:</em>

<em>    print("Invalid")</em>

7 0
3 years ago
If you want to share files on your computer with other Windows computers, what should you have installed and enabled on your com
Troyanec [42]

Answer: One Drive

Explanation:

5 0
3 years ago
Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the g
zepelin [54]

Answer:

Explanation:

The following is written in C++ and asks the user for inputs in both miles/gallon and dollars/gallon and then calculates the gas cost for the requested mileages using the input values

#include <iostream>

#include <iomanip>

using namespace std;

int main () {

   // distance in miles

   float distance1 = 20.0, distance2 = 75.0, distance3 = 500.0;

   float miles_gallon, dollars_gallon;

   cout << "Enter cars miles/gallon: "; cin >> miles_gallon;

   cout << "Enter cars dollars/gallon: "; cin >> dollars_gallon;

   cout << "the gas cost for " << distance1 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance1 / miles_gallon << "$\n";

   cout << "the gas cost for " << distance2 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance2 / miles_gallon << "$\n";

   cout << "the gas cost for " << distance3 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance3 / miles_gallon << "$\n";

   return 0;

}

8 0
3 years ago
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