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Gemiola [76]
3 years ago
11

Arrange the following is ascending order -12 8 -14 6 0

Mathematics
2 answers:
Nataliya [291]3 years ago
4 0

Answer:

-14, -12, 0, 6, 8

Step-by-step explanation:

lora16 [44]3 years ago
3 0

Answer: -14, -12, 0, 6, 8

Step-by-step explanation:

This is correct because -14 is the number with the smallest value so it belongs last. Then comes -12, 0, 6, 8.

Hope this helps ;)

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Solve 5(-3)/3(-2)+2^2
Iteru [2.4K]

Answer:

14

Step-by-step explanation:

2^2=4

5*-3= -15

-15/3=-5

-5*-2=10

10+4=14

6 0
4 years ago
What is 3 times -3 Please help me
Lyrx [107]
-9 because if you multiply a positive by a negative it equals a negative.
8 0
3 years ago
Read 2 more answers
Write the point-slope equation of the line that passes through(3,5) and (7,1)
Liono4ka [1.6K]

Answer:   y - 1 = –(x –7)

or   y –5 = –1(x –3)

The attachment shows the graph of these equations (identical)

Step-by-step explanation:

The basic form for a point-slope equation is

y - b = m(x - a)

a is the x-value from the given coordinate,  b is the y-value form the given coordinate,  m is the slope. x and y are the variables in the function.

To find the slope, m, use the given coordinates. Get the difference in the y-values and divide by the difference in the x-values. This is "rise over run."

Subtract the first coordinate from the second coordinate.

Given coordinate points: ​(3​,5) and ​(7​,1)    substitute values:

m= 1 –5 / 7 –3  becomes  m= –4/4   so the slope, m = –4/4

That is –1  The "1" is "understood," so only the negative sign represents the slope  in the equation

To write the equation:  Take the basic form, substitute b and a values from either given coordinate. And use the value of m we just calculated.

y - b = m(x - a)  Using the second coordinate: (7,1)

y - 1 = –(x –7)

or using the first coordinate:

y –5 = –(x –3)

5 0
3 years ago
How would you factor
Svetach [21]
\bf 4x^3+2x^2+2x\implies 2x(2x^2+x+1)

so in short, the only factoring doable to it, without any complex factors, is that of taking the common factor of 2x.

now, the trinomial of 2x²+x+1, will not give us any "real roots", just complex or "imaginary" ones.

if you have already covered the quadratic formula, you could test with that, or you can also check that trinomial's discriminant, and notice that it will give you a negative value.

\bf \begin{array}{llcccll}
& 2 x^2& +1 x& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad \qquad 1^2-4(2)(1)
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}
5 0
3 years ago
Read 2 more answers
Could someone please help me
Juli2301 [7.4K]

Answer:

c

Step-by-step explanation:

I think its c but I could be wrong

7 0
3 years ago
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