Answer:
g(x) = 3x² + 7
Step-by-step explanation:
Given f(x) then f(x) + c is a vertical translation of f(x)
• If c > 0 then shift up by c units
• If c < 0 then shift down by c units
Here the translation is 5 units up, thus
g(x) = 3x² + 2 + 5 = 3x² + 7
Answer:
A
Step-by-step explanation:
slope is change in y over change in x, line goes down 4, right three whole units, making the slope -4/3
y-intercept is where the line hits the y-axis
the line hits the y-axis at (0,8)
this makes the y-intercept 8
The answer is 1.7325
1x5=5
1x2=2
1x8=8
Add a zero
2x5=10
2x2=4
2x8=40
Add a Zero
All the answers to the next number will all be zero.
Add that all together.
Answer:
1:50 P.M
Step-by-step explanation:
12:15+35 = 12:50
1 hour = 60 minutes
60 + 12:50 = 1:50
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
