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Karo-lina-s [1.5K]

2 years ago

6

Lena starts a spelling test at 12:15 P.M. The test is 35 minutes long. After the spelling test, Lena has art class for 1 hour. W

hat time does Lena's art class end?

1 answer:

saul85 [17]2 years ago

8 0

Answer:

1:50 P.M

Step-by-step explanation:

12:15+35 = 12:50

1 hour = 60 minutes

60 + 12:50 = 1:50

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How does a sequence of translations, reflections, and rotations result in congruent figures?

yaroslaw [1]

Answer:

Rotations, reflections, and translations are isometric. That means that these transformations do not change the size of the figure. If the size and shape of the figure is not changed, then the figures are congruent.

Step-by-step explanation:

5 0

2 years ago

Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).

Vanyuwa [196]

$L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)$

$R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R$

5 0

2 years ago

Read 2 more answers

Calculate the distance between the points (-6, 4) and (5, -1). Round to the nearest tenth.

ludmilkaskok [199]

It will be 42 because of the with times the 2nd highest

4 0

2 years ago

Please help me ASAP a newspaper publishes the following headline: if the weather is sunny this weekend then the kite festival wi

Pepsi [2]

The answer is the second choice because since it is raining then, the conditional statement was false.

6 0

3 years ago

If f(x)=x^2-7 and h(x)=7x-5, then f(h(2))=

zaharov [31]

We are given 3 equations. Using these equations we can find f(h(2)).

h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9

f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74

so f(h(2))=74

5 0

3 years ago