Answer:
The term "El Nino" refers to the warming of the central and eastern tropical Pacific waters that occurs every 3 to 7 years and typically lasts from 9 to 12 months. The 1997-1998 El Nino, the strongest ever recorded, affected climate patterns worldwide. Its effect, combined with an increasing trend in annual global temperatures, made 1998 the warmest year in the 20th century. Suppose you are a climatologist. You conduct a hypothesis test to determine whether the global mean temperature in the current year is different from the global mean temperature in 1998. Assume that the global mean temperature in 1998 is 14.3 degrees Celsius. You obtain a preliminary sample of temperatures from recording stations worldwide, which yields a sample mean of x bar = 15.1 degrees Celsius. Let mu denote the global mean temperature in the current year. Formulate your null and alternative hypotheses by selecting the appropriate values in the blue drop-down menus that follow.
<h2><em>hope</em><em> it</em><em> helps</em><em> you</em></h2>
<em>sorry</em><em> </em><em>i</em><em>f </em><em>it's </em><em>not</em><em> </em><em>helpful</em><em> </em>
<em>have </em><em>a </em><em>good</em><em> day</em>
Answer:
6 dollars per hour
Step-by-step explanation:
We can set up and solve an equation to answer this question. For this problem, let x stand for the amount he earned per hour. The equation that represents this situation is 3.2x + 4.3x = 45. The first term represents monday and the second represents tuesday. When these add up they should equal 45 because that is the total amount he made. To find his pay per hour, solve for x.
First, combine the like terms
Next, divide both sides by 7.5
Hourly rate:
39(1.3r) = 541.80
(hours times hourly rate equals profit)
then solve
1.3r = 13.89
r = 10.69
the hourly rate is $10.69
to answer the bottom question, 390 + 117 = 507, but that’s not close to 541.80 so I have no idea what they’re asking there
Ok, if you say so. Jean took 1/2 hour to complete 3/8 of a math problem.
Answer:

Step-by-step explanation:
Given


Required
Determine the probability before the request of past experience
In this case, we only consider the 50 50 chance probability


