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saw5 [17]
3 years ago
15

Rochelle's car averages 32.5 miles per gallon on the highway. at that rate, how many gallons of gaswill her car use for driving

on the highway for 260 miles?
Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0
32.5 miles per gallon

so for 260 miles......260/32.5 = 8 gallons <=
Mademuasel [1]3 years ago
4 0

Answer:

8 gallons

Step-by-step explanation:

260 miles divided by 32.5 miles per gallon

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Co...
Julli [10]

Answer:

16

Step-by-step explanation:

Multiplecation by the length width, and the height, then divide and its 16.

8 0
3 years ago
What is the simplified form of this?
s2008m [1.1K]

Answer:

D is the answer

Step-by-step explanation:

8 0
3 years ago
How to find trigonomic ratio ​
ycow [4]

Answer:divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.

Step-by-step explanation:

divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.

7 0
4 years ago
How do you illustrate<br>quadratic equation<br>in one variable?​
soldi70 [24.7K]

Step-by-step explanation:

Quadratic Equation

Quadratic equation is in the form

ax2+bx+c=0

Where

a, b, & c = real-number constants

a & b = numerical coefficient or simply coefficients

a = coefficient of x2

b = coefficient of x

c = constant term or simply constant

a cannot be equal to zero while either b or c can be zero

Examples of Quadratic Equation

Some quadratic equation may not look like the one above. The general appearance of quadratic equation is a second degree curve so that the degree power of one variable is twice of another variable. Below are examples of equations that can be considered as quadratic.

1. 3x2+2x−8=0

2. x2−9=0

3. 2x2+5x=0

4. sin2θ−2sinθ−1=0

5. x−5x−−√+6=0

6. 10x1/3+x1/6−2=0

7. 2lnx−−−√−5lnx−−−√4−7=0

For us to see that the above examples can be treated as quadratic equation, we take example no. 6 above, 10x1/3 + x1/6 - 2 = 0. Let x1/6 = z, thus, x1/3 = z2. The equation can now be written in the form 10z2 + z - 2 = 0, which shows clearly to be quadratic equation.

Roots of a Quadratic Equation

The equation ax2 + bx + c = 0 can be factored into the form

(x−x1)(x−x2)=0

Where x1 and x2 are the roots of ax2 + bx + c = 0.

Quadratic Formula

For the quadratic equation ax2 + bx + c = 0,

x=−b±b2−4ac−−−−−−−√2a

See the derivation of quadratic formula here.

The quantity b2 - 4ac inside the radical is called discriminat.

• If b2 - 4ac = 0, the roots are real and equal.

• If b2 - 4ac > 0, the roots are real and unequal.

• If b2 - 4ac < 0, the roots are imaginary.

Sum and Product of Roots

If the roots of the quadratic equation ax2 + bx + c

= 0 are x1 and x2, then

Sum of roots

x1+x2=−ba

Product of roots

x1x2=ca

You may see the derivation of formulas for sum and product of roots here.

4 0
4 years ago
A bookstore bought a case of 10 books at a wholesale price of $84. The bookstore will sell the books at a 25 percent markup, and
Nata [24]
All you have to do is multiply 84 by 25%

And that's your answer.

I hope this helped
4 0
4 years ago
Read 2 more answers
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