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saw5 [17]
3 years ago
15

Rochelle's car averages 32.5 miles per gallon on the highway. at that rate, how many gallons of gaswill her car use for driving

on the highway for 260 miles?
Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0
32.5 miles per gallon

so for 260 miles......260/32.5 = 8 gallons <=
Mademuasel [1]3 years ago
4 0

Answer:

8 gallons

Step-by-step explanation:

260 miles divided by 32.5 miles per gallon

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What is the answer to 20(x + 1) = 200
patriot [66]

Answer:

x = 9

Step-by-step explanation:

20x + 20 = 200

-20 -20

20x. = 180

x = 9

6 0
3 years ago
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Rewrite the expression −7/8 − 2 1/4 ​as the sum of two numbers.
pychu [463]

Answer:

-3 1/8.

Step-by-step explanation:

−7/8 − 2 1/4

= -7/8 + -9/4

= -7/8 - 18/8

= -25/8

= -3 1/8.

4 0
3 years ago
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
Twins Isaac and Isaac where just born. Issac weighs 6 pounds 2 ounces and Isaiah weighs 5 pounds 4 ounces how many ounces do the
Ray Of Light [21]
182 ounces isthe answer
3 0
4 years ago
A building across the street casts a shadow that is
tensa zangetsu [6.8K]

Answer:

The building is 36 feet tall.

Step-by-step explanation:

Divide 6 by 4 then multiply by 24.

3 0
4 years ago
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