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nataly862011 [7]
2 years ago
10

If a DNA codon changes from TTA to TTC, what amino acid would the matching mRNA sequence code for?

Biology
1 answer:
Marina86 [1]2 years ago
5 0

Answer:

TTC codon encodes for Phenylalanine (Phe)

Explanation:

A codon (also known as a nucleotide triplet) is a sequence of DNA or RNA composed of three consecutive nucleotides. During protein synthesis, each codon specifies a particular amino acid or stop signal (i.e., termination codons). There are 64 possible codons, 61 encode for amino acids, while three (3) codons represent stop signals (e.g., UAG, UAA, UGA). In this case, TTC (i.e., UUC codon in the mRNA) codon encodes the amino acid Phenylalanine, while TTA (i.e., UUA codon in the mRNA sequence) codon encodes the amino acid Leucine.

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Duchenne muscular dystrophy is an X-linked recessive disease. A phenotypically normal couple wants to start a family. The woman’
Andreyy89

Answer:

\frac{1}{8}

Explanation:

From the question: Duchenne muscular dystrophy is an X-linked recessive disease.

Now for an X-linked recessive disorder to be affected by a male individual; it only requires the presence of only one copy of the recessive allele of the disease to be present BUT in a female individual. both copies of the recessive allele must be present.

Let the X-linked recessive disease(i.e Duchenne muscular dystrophy) be = (ⁿ)

However, we are told that the couples are normal and are unaffected. Therefore;

the male partner (XY) will be:   X^NY

the female partner (XY) will be: X^NX^N

Similarly, the question proceeds by telling us that: the woman's brother has the disease.

Definitely, it's possible that this unaffected woman is a carrier of the disease.

So, if she is a carrier; we have her traits to be: X^NX^n

NOW, if a cross exist between these couples; we have

X^NY     ×        X^NX^n

                     X^N                         Y

X^N                X^NX^N                  X^NY

X^n                 X^NX^n                   X^nY

So, we have offspring as follows:

X^NX^N  = normal unaffected female  

X^NY     = normal unaffected male

X^NX^n   = female carrier for the Duchenne muscular dystrophy disease

X^nY      = affected male with the Duchenne muscular dystrophy disease

So, the probability of the child to be affected with the disease = \frac{1}{4}

Also, the probability that the first child will be a male or a female = \frac{1}{2}

∴

the  probability that the couple’s first child will be affected = \frac{1}{4}*\frac{1}{2}

=\frac{1}{8}

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3 years ago
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