Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. In addi
tion, suppose that a dominant allele (L) codes for long eyelashes and a recessive allele (l) codes for short eyelashes. If two individuals heterozygous for both traits (tail color and eyelash length) mate, what's the probability of the phenotypic combinations of the offspring? A. 1:1 ratio (half are polka-dot tails and short eyelashes; half are solid tails and long eyelashes) B. 1:1 ratio (half are polka-dot tails and long eyelashes; half are solid tails and short eyelashes) C. 9:3:3:1 ratio (9 polka-dot tails and long eyelashes, 3 polka-dot tails and short eyelashes, 3 solid tails and short eyelashes, 1 solid tail and short eyelash) D. 9:3:3:1 ratio (9 polka-dot tails and short eyelashes, 3 polka-dot tails and short eyelashes, 3 solid tails and long eyelashes, 1 solid tail and long eyelash)
If two individual are heterozygous for both traits then there genotype will each look like this PpLl. To find the probability, you need to do a cross with both traits. Each parent has the possibility of giving the following combinations: PL, Pl, pL, pl.
Polka dot tail/ long lashes: 9/16 Polka dot tail/ short lashes: 3/16 Solid Tail / long lashes: 3/16 solid tail/ short lashes 1/16
The answer is (C) 9:3:3:1 ratio with 9 polka dot tails and long eyelashes, 3 polka dot tails and short eyelashes, 3 solid tails and long eyelashes (there seems to be a typo in the question) and 1 short tail short eyelash
At pH 2 the net charge of the R groups of all the amino acids that comprise the peptide in question would be positive. This happens because of the high content of protons in a solution of pH 2, a value that is below the isoelectric point of all the amino acids. Since the peptide would have a positive net charge, it would migrate to the negative terminal of the gel because opposite charges attract each other.
