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3 years ago

7

The median of $20, x, 15, 30, 25$ is $0.4$ less than the mean. If $x$ is a whole number, what is the sum of all possible values

of $x$?

1 answer:

34kurt3 years ago

5 0

Answer:

198

Step-by-step explanation:

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Make x the subject of m=n + x/p

marshall27 [118]

Answer:

$\boxed{x = p(m - n)}$

Step-by-step explanation:

$= > m = n + \frac{x}{p} \\ \\ = > m = (n \times \frac{p}{p} ) + \frac{x}{p} \\ \\ = > m = \frac{pn}{p} + \frac{x}{p} \\ \\ = > m = \frac{pn + x}{p} \\ \\ = > mp = pn + x \\ \\ = > x + pn = pm \\ \\ = > x = pm - pn \\ \\ = > x = p(m - n)$

4 0

3 years ago

How do you solve this equation? 8=3(q-10)-10

IRISSAK [1]

Q = 16
View the attached image for work!

6 0

3 years ago

Joshua walked 14 feet down the hall of his house to get the door he continued in a straight line out the door and across the yar

AleksandrR [38]

Answer:

Joshua walked 48 feet in total.

Step-by-step explanation:

To find the total distance we need to sum every distance that he walked. We have:

- First: Joshua walked down the hall to the door = 14 feet

- Second: He continued in a straight line out the door and across the yard to the mailbox = 24 feet

- Third: He came straight back across the yard and stopped to pet his dog = 10 feet

Hence, the total distance is:

$d_{T} = d_{1} + d_{2} + d_{3} = 14 ft + 24 ft + 10 ft = 48 ft$

Therefore, Joshua walked 48 feet in total.

I hope it helps you!

8 0

3 years ago

julsineya [31]

Answer:

Her multiplication

Step-by-step explanation:

Not really an aexplanation

8 0

3 years ago

Which of the following are solutions to the equation sinx cos(pi/7)-sin(pi/7)cosx=sqrt(2)/2

Arturiano [62]

The solution would be like this for this specific problem:

sin ( x - ( pi / 7 ) ) = - sqrt ( 2 ) / 2
x - ( pi / 7 ) = - pi / 4 + 2n*pi or x - ( pi / 7 ) = (5pi / 4 ) + 2n*pi
x = ( pi / 7 ) - ( pi / 4 ) + 2n*pi or x = ( 5pi / 4 ) + ( pi / 7 ) + 2n*pi
x = ( - 3pi / 28 ) + 2n*pi

<span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

6 0

3 years ago

Read 2 more answers