Remember that the vertex form of a parabola or quadratic equation is:
y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola (and a is half the acceleration of the of the function, but that is maybe too much :P)
In this case we are given that the vertex is (1,1) so we have:
y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:
-3=a(0-1)^2+1
-3=a+1
-4=a so our complete equation in vertex form is:
y=-4(x-1)^2+1
Now you wish to know where the x-intercepts are. x-intercepts are when the graph touches the x-axis, ie, when y=0 so
0=-4(x-1)^2+1 add 4(x-1)^2 to both sides
4(x-1)^2=1 divide both sides by 4
(x-1)^2=1/4 take the square root of both sides
x-1=±√(1/4) which is equal to
x-1=±1/2 add 1 to both sides
x=1±1/2
So x=0.5 and 1.5, thus the x-intercept points are:
(0.5, 0) and (1.5, 0) or if you like fractions:
(1/2, 0) and (3/2, 0) :P
The answer is 3 and you get that by using the formula for the area of rectangle, p=2L+2W
44=2(4+5w) + 2w
44=8+10w + 2w
44=8+12w
44-8=8+12w-8
36=12w
36/12=12w/12
3=w
If you plug 3 back into the original formula then you see that it is equal to the perimeter of 44
P=2(4+5w) + 2w
P=2(4+5•3) + 2(3)
P=2(19) +6
P=38+6
P=44
Answer:
i cant see it
Step-by-step explanation:
I’m guessing it’s 9x^2 -6x + 1 but this is basically just one. (1/3,0) use desmos if you’re curious
X = 112
Sorry I had to smoosh the image so it would fit.
