Answer:
NO
Step-by-step explanation:
Note :
Consider a triangle with sides‘s length a , b and c
triangle inequalities state that we must have c - a < b < c + a
now , is the third side always the longest ?
the answer is NO: (let’s take a counter example )
in a triangle with 2 sides‘s length 3 , 4
the third side could measure 2
because 4-3 < 2 < 4+3
Answer:
For number 3 the answer is -4
Answer:
![\sqrt[5]{x - 9}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%20-%209%7D%20)
Step-by-step explanation:
y=x^5+9
To find inverse function make x the subject, first:
y=x^5+9
y - 9 = x^5
x = ![\sqrt[5]{y - 9}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%20-%209%7D%20)
![y^{-1} = \sqrt[5]{x - 9}](https://tex.z-dn.net/?f=y%5E%7B-1%7D%20%20%3D%20%5Csqrt%5B5%5D%7Bx%20-%209%7D%20)
so inverse function of y=x^5+9 is
Answer:
∠ABC ≅ ∠DEC
∠DEC = ∠GEF
thus:
∠ABC = ∠GEF
∠GFE ≅ ∠DCE
∠DCE = ∠ACB
thus:
∠ACB = ∠GFE
If two of their angles are equal, then the third angle must also be equal, because angles of a triangle always add to make 180°.
thus: ΔABC ∼ ΔGEF by AA similar triangle postulate
I hope this helps
The answer is 50/99 because it isn't ending so you can't say to the hundredths or thousandths place because it isn't so u make it out of 99 because it goes on forever hope this helped mark brainiest if i helped
