Please help as soon as possible

A red ballon starts at 7 meters off the ground and rises at 3 meters per second. A ballon starts at 12 meters off the ground and

GrogVix [38]

Let x be the no. of seconds it takes for the balloons to be at the same height.
7+3x = 12+2x
Deduct both sides by 2x.
7+x = 12
Deduct both sides by 7.
x = 5
Ans: It will take 5 seconds for the balloons to be at the same height.

4 0

3 years ago

A biologist is studying rainbow trout that live in a certain river and she estimates their mean length to be 529 millimeters. As

vredina [299]

Answer:

See the book it will definitely help you

7 0

3 years ago

Eli lives 3 3/4 miles from the library. He decided to bike from his home to the library to return some books. Eli biked 1 1/10 m

KIM [24]

Eli traveled a total of 8.6 miles. He went to the library and back. 3.75 + 3.75. and he also added and extra 1 1/10 mile. so, 3.75 x 2 = 7.5, 7.5 + 1 1/10 = 8.6. Hope that helped!

7 0

3 years ago

Read 2 more answers

Find the differential coefficient of <img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

15+0= 15

Ksju [112]

First of all, let's take a look on the question.

$\large{15 + 0 = 15}$

Here, 0 is added to 15 and the resultant is 15 only. So, we can say that 0 when added with any number gives the same number as the resultant.

So, the property is known as Identity property because 0 is added to get the identity of the same number.

The Correct Option:

$\large{ \boxed{ \red{ \bf{Option \: C}}}}$

So, let's know more...

Commutative property ➝ a + b = b + a
Associative property ➝ a + (b + c) = (a + b) + c
Distributive property ➝ a(b + c) = ab + ac

So this is the general form of these properties which is general observed in the rational numbers.

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5 0

3 years ago