How to calculate slope for a line that goes through
1 answer:
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Answer:
Brainiest would be appreciated
High Hopes^^
Barry-
Check the picture below.
so the focus point is there, and the directrix is above it, meaning is a vertical parabola and is opening downwards, since the parabola opens up towards the focus.
now, the vertex is half-way between those two guys, at a "p" distance from either one, if we move over the y-axis from -5 to +2, we have 7 units, half-way is 3.5 units, and that puts us at -1.5 or -1½, as you see in the picture, so the vertex is then at (-3 , -1½).
so the distance from the vertex to the focus point is then 3½ units, however since the parabola is opening downwards, "p" is negative, thus "p = 3½".
Answer:
The present was 300 feet above ground 5 seconds after being thrown.
6.47 seconds passed before the present hit the ground.
Step-by-step explanation:
We have the following quadratic function
Which determines the height of the present.
Determine when the present was 300 feet above the ground.
This is when . So
This is and
. There are no negative time instants. So the present was 300 feet above ground 5 seconds after being thrown.
Determine how many seconds passed before the present hit the ground.
This is t when
6.47 seconds passed before the present hit the ground.