All categories

3 years ago

Can anyone please help. this is my last question!!!!

Mathematics

1 answer:

Andrej [43]3 years ago

8 0

9514 1404 393

Answer:

x = 3.6

Step-by-step explanation:

The angle bisector divides the triangle proportionally.

The base segment to the right of the bisector is 6-x, so we can write the proportion ...

x/6 = (6-x)/4

Multiplying by 12, we get ...

2x = 3(6 -x)

5x = 18 . . . . . add 3x

x = 18/5 . . . . divide by 5

x = 3.6

_____

<em>Alternate solution</em>

Since the base of the triangle is given as a left-part and a sum-of-both-parts, we can write the proportion the same way:

left-part / sum-of-both-parts = x/6 = 6/(6+4)

Then the solution is x = 6(6/10) = 36/10 = 3.6.

Doing it this way avoids having x on both sides of the equation, so makes solving the equation be "one step."

You might be interested in

HELP PLSSSSS PLSSSS I NEED HELPPPPPPP ASAPPPPP

Hitman42 [59]

I would say A (7) but I’m not 100% sure.

5 0

2 years ago

Solve T = 7c-2d for d.

stepladder [879]

Answer:

$d = \frac{t - 7c}{ - 2}$

Hope this helps at all. :)

4 0

3 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

3 years ago

Need help fast Thank

ollegr [7]

What you need help with

3 0

3 years ago

Can somebody help me please

Veseljchak [2.6K]

Step-by-step explanation:

yes its ans is (3,3) fast you have see in x axis then y axis .so according to this we write 3 which lies in x- axis and then another 3 which lies in y-axis.

3 0

2 years ago