You have a system of equations

.
1. Substitude right side of second equation into the left side of the first equation:

.
2. Solve this equation:

.
3. Find y:
for

,
for

.
4. The solutions of the system are: (3,-12) and (5,-24).
Answer: Correct choice is A.
A because the origin is at 0,0 and point A is at 0,0
<h3>
<u>Answer:</u></h3>

<h3>
<u>Step-by-step explanation:</u></h3>
A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.
The inequality given to us is :-

Let's plot a graph to see its interval . Graph attached in attachment .
Now we can see that the Interval notation of would be ,
![\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Corange%20%5Ctt%20%5Cpurple%7B%5Cleadsto%7Dy%20%5Cin%20%5B-2%2C-1%5D%20%7D%7D)
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<u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
Answer:
11. x = 6; y = 6.5
12. x = 2; y = 4
Step-by-step explanation:
In each figure, the hash marks on the lines indicate the parallel lines (marked with red arrows) are equally-spaced. That means the two expressions involving x are equal to each other, and the two expressions involving y are equal to each other.
__
11. 2x +1 = x +7
x = 6 . . . . . . . subtract (x+1) from both sides
and
3y -8 = y +5
2y = 13 . . . . add (8-y) to both sides
y = 6.5 . . . . divide by the coefficient of y
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12. x +3 = 3/2x +2
1 = 1/2x . . . . . subtract (x+2)
2 = x . . . . . . . multiply by 2
and
2y -1 = 3y -5
4 = y . . . . . . add (5 -2y)
Answer:
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