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strojnjashka [21]
2 years ago
10

En las olimpiadas de Matemática. Roció represen a su colegio. La prueba consistía en 60 problemas. Cada respuesta correcta valía

4 puntos y por cada respuesta incorrecta había un punto en contra. Luego del examen. Roció obtuvo un puntaje de 155. Ella respondió todas las preguntas y desea saber cuantas fueron correctas y cuantas incorrectas
Mathematics
1 answer:
PtichkaEL [24]2 years ago
5 0

Answer:

Rocío respondió 43 preguntas correctas y 17 incorrectas.

Step-by-step explanation:

Dado que en las olimpiadas de Matemática, Rocío representó a su colegio, y la prueba consistía en 60 problemas, de los cuales cada respuesta correcta valía 4 puntos y por cada respuesta incorrecta había un punto en contra, y luego del examen, Rocío obtuvo un puntaje de 155, y ella respondió todas las preguntas y desea saber cuantas fueron correctas y cuantas incorrectas, para determinar dicha duda se debe realizar el siguiente calculo:

60 x 4 = 240

40 x 4 - 20 = 140

45 x 4 - 15 = 165

42 x 4 - 18 = 150

43 x 4 - 17 = 155

Por lo tanto, Rocío respondió 43 preguntas correctas y 17 incorrectas.

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tia_tia [17]

Answer: You are incorrect, the slope is correct, but the actual y-intercept is 205 ft.

Then the equation is:

y = (-15 ft/min)*x + 205 ft

Step-by-step explanation:

Ok, let's solve this.

We know that water is drained from a reservoir, let's assume that we can model this situation with a linear relation:

y = a*x + b

Where x is time, y is the height of the water in the reservoir, a is the slope (in this case represents how much changes the height of the water in the reservoir in one unit of time) and b is the initial height of the water in the reservoir.

We know that for a line that passes through the points (x₁, y₁) and (x₂, y₂) the slope is:

a = (y₂ - y₁)/(x₂ - x₁)

For this particular case we know that after 2 minutes the height of the water is 175 ft, then we have the point (2 min, 175 ft)

and after 5 minutes (so 7 minutes in total), the height of the water is 100ft, then: (7 ft, 100ft)

Then the slope of this:

a = (100 ft - 175 ft)/(7 min - 2 min) = (-75ft/5min) = - 15 ft/min

Then our line is something like:

y = (-15ft/min)*x + b

To find the value of b, we can use the fact that when x = 2 min, y = 175 ft

So if we replace these two values in the equation we get:

175ft = (-15 ft/min)*2 min + b

175 ft = -30 ft + b

175 ft + 30 ft = b                  

(here is your problem, it seems like you subtracted instead of adding in this part)

205 ft = b

Then the equation is:

y = (-15 ft/min)*x + 205 ft

So you are incorrect (but only for a little bit), you computed wrong the y-intercept.

3 0
3 years ago
ladder is 8 ft long . The ladder needs to reach to a window that is 6 ft above the ground . How far away from the house should t
stiks02 [169]

Answer:

5.3 or 28

Step-by-step explanation:

6^{2}+b^{2}=8^{2}

36+b^{2}=64

64-36=28

\sqrt{28\\}

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5 0
2 years ago
Please help me with this ASAP.
Simora [160]

Answer:

C

Step-by-step explanation:

If you add the first equation up you get 2z+6 by combining like terms

if you see A a is equal to 3z+6 so a doesn’t work

If you look at B b is equal to z+12 so b doesn’t work

finally C if you distibute it out you get 2(z)+2(3) which equal 2z+6 which works

C

7 0
2 years ago
Julio says,"If you subtract 15 from my number and multiply the difference by -7,the result is -175." What is Julios number
maw [93]

Answer: 40

Step-by-step explanation:

Assume Julio's number is x.

The expression would be:

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x - 15 = -175/-7

x = -175/-7 + 15

x = 40

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2 years ago
The sum of the first terms of an Arithmetic progression (Ap) is 130.if the fifth term is 3times,the first term,find the (a)commo
Nadusha1986 [10]

Answer:

For part a)

130 = 10/2[2a+(10-1)d]

Simplify, u get

2a + 9d = 26.................(1)

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Simplify, u get

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Substituting for a in equation 1,

2(2d)+9d= 26

Solving for d, we get

d = 2

In part b) substituting for d in equation 2 to get the first term

a = 2(2) = 4

Part c) the no. of terms required can be obtained by solving

28 = 4+(n-1)2

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3 years ago
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