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rewona [7]
3 years ago
14

A football team scored fewer than 16 points in Saturday’s game. Than wants to write an inequality for the number of points. He u

ses the variable s in his inequality. What does s represent? a.the number of fans of the team b.the number of games played by the team c.the number of points scored by the team d.the number of players on the team
Mathematics
2 answers:
GalinKa [24]3 years ago
6 0
C. the number of points scored by the team
strojnjashka [21]3 years ago
4 0

Answer:

C. the number of points scored by the team

Step-by-step explanation:

A football team scored fewer than 16 points in Saturday’s game.

Than wants to write an inequality for the number of points.

He uses the variable 's' in his inequality.

The inequality must be = s

This means the scores points are less than 16.

Therefore, the correct answer is - C. the number of points scored by the team

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GrogVix [38]

Answer:

1/12

Step-by-step explanation:

The whole circumference (i.e complete circle) is an arc which measures 360°

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the fraction of our arc of 30° to the complete circle of 360° is

30/360

= 3/36

= 1/12

5 0
3 years ago
Please solve with working much appreciated
Oduvanchick [21]

Answer:

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Step-by-step explanation:

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4 0
4 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
Help help help please ​
Veronika [31]

Answer:

{9,14,20}

Step-by-step explanation:

hope it helps

8 0
2 years ago
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Uma volta inteira na Terra corresponde a uma distância 2πr≅40.000 km. Se um satélite leva 85 minutos para dar uma volta completa
Shalnov [3]

Answer:

7.8. 10 ^ 3 m / s

Step-by-step explanation:

The computation of the average speed in m/s is shown below:

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= ΔS ÷ Δt;

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= 7.8. 10 ^ 3 m / s

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3 years ago
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