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3 years ago

Please Help! Thank you in advance!!

Mathematics

1 answer:

satela [25.4K]3 years ago

7 0

Answer:

a dilation with a scale factor less than 1 and then a translation

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Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at

Oksanka [162]

a) The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively.

b) The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

$P'(x,y) = k\cdot P(x,y)$ (1)

Where:

$P(x,y)$ - Original point
$P'(x,y)$ - Dilated point.

If we know that $k = \frac{1}{3}$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ , then the new points of the quadrilateral are:

$A'(x,y) = \frac{1}{3}\cdot (0,6)$

$A'(x,y) = (0, 2)$

$B'(x,y) = \frac{1}{3} \cdot (-3,-6)$

$B'(x,y) = (-1, -2)$

$C'(x,y) = \frac{1}{3}\cdot (-9,-6)$

$C'(x,y) = \left(-3,-2\right)$

$D'(x,y) = \frac{1}{3}\cdot (-12,-3)$

$D'(x,y) = (-4, -1)$

The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively. $\blacksquare$

b) A translation along a vector is defined by following operation:

$P'(x,y) = P(x,y) +T(x,y)$ (2)

Where $T(x,y)$ is the transformation vector.

If we know that $T(x,y) = (-5,-1)$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ ,

$A'(x,y) = (0,6) + (-5, -1)$

$A'(x,y) = (-5, 5)$

$B'(x,y) = (-3, -6) + (-5, -1)$

$B'(x,y) = (-8,-7)$

$C'(x,y) = (-9, -6) + (-5, -1)$

$C'(x,y) = (-13, -7)$

$D'(x,y) = (-12,-3)+(-5,-1)$

$D'(x,y) = (-17, -4)$

The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively. $\blacksquare$

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

7 0

3 years ago

Let w=width and 4 + w=

kozerog [31]

Answer:

Part 1 : $w^2+4w-60=0$

Part 2 :

w=6

l = 10

Step-by-step explanation:

Part 1:

Let the width of the rectangle = w

Length of the rectangle = w + 4

Area of the rectangle is given as

60 Sq Yrds

$60=w(w+4)$

$60=w^2+4w$

$w^2+4w-60=0$

Hence this expression represents the area of the rectangle. Solving which for w will give us the width of the rectangle.

Part 2:

(w+10)(w-6)= 0

either (w+10) = 0

(w-6)=0

or both are zero

(w+10) = 0 ⇒ w = -10

not possible as the dimension can not be 0

(w-6)=0 ⇒ w=6

Hence the width is 6 yards

And thus the length will be 6+4 = 10 yards

8 0

3 years ago

(y-3)(y+10) find the product please

allochka39001 [22]

Answer:

y^2 +7y-30

Step-by-step explanation:

Step 1: Use FOIL

y·y = y^2

y· 10= 10y

-3·y= -3y

-3·10= -30

Step 2: <em>combine like terms</em>

y^2+ 10y-3y-30

7^2+ 7y-30

and thats all :)

hope this helped

4 0

3 years ago

Read 2 more answers

Which graph represents the solution set for the system 2x + 5y ≤ 9 and 3x + 5y ≤ 9?

Solnce55 [7]

The answer is graph B. Have a nice day!

6 0

3 years ago

Read 2 more answers

31 days x 160 residents=

k0ka [10]

Answer:

4960?

Step-by-step explanation:

31 times 160 = 4960

5 0

3 years ago