The smallest of two integers is 61
Step-by-step explanation:
Let x be the smaller integer
Then the next integer will be:
x+1
According to given statement that the sum of both is 123
Subtracting 1 from both sides
Dividing both sides by 2
The smallest of two integers is 61
Keywords: Linear equations, Variables
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Answer:
two real, unequal roots
Step-by-step explanation:
y is definied as y = 3x - 1. Substitute 3x - 1 for y in xy = 9, obtaining:
x(3x - 1) = 9. Then:
3x^2 - x - 9 = 0. In this quadratic, the coefficients are a = 3, b = -1 and c = -9.
Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109. Because the discriminant is positive, we have two real, unequal roots.
If you are factoring then the answer is 1/7 x (14z-97) but if your simplifying then it’s 2z- 97/7
Answer:
11 and 13
Step-by-step explanation:
the first (smaller) odd integer can be called x
the second (larger) odd integer can be called x+2
2(x+2)+x = 37
<em>[simplify . . .]</em>
2x+4+x = 37
3x+4 = 37
<em>[subtract 4 from each side]</em>
3x = 33
<em>[divide each side by 3; find smaller odd integer]</em>
x = 11
<em>[add 2 to find larger odd integer]</em>
x+2 = 13
