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Dafna11 [192]
3 years ago
10

Av citi auon

Physics
1 answer:
ddd [48]3 years ago
7 0
Dm me for the answer
You might be interested in
What is the lift (in newtons) due to Bernoulli's principle on a wing of area 96 m2m2 if the air passes over the top and bottom s
egoroff_w [7]

Answer:

F_{lift}=2.42*10^{9} N

Explanation:

Apply Bernoulli's principle

p_{b}+1/2pv_{b}^{2} =p_{t}+1/2pv_{t}^{2} \\p_{b}-p_{t}= 1/2pv_{t}^{2}-1/2pv_{b}^{2}\\p_{b}-p_{t}= 1/2(1.00*10^{3}  kgm^{-3} )(270m/s^{2} )-1/2(1.00*10^{3}kgm^{-3} )(150m/s^{2} )\\p_{b}-p_{t}=2.52*10^{7}N/m^{2}\\  F_{lift}=2.52*10^{7}N/m^{2}*96m^{2} \\ F_{lift}=2.42*10^{9} N

5 0
4 years ago
Suppose a distant world with surface gravity of 5.20 m/s2 has an atmospheric pressure of 7.16 ✕ 104 Pa at the surface. (a) What
Nesterboy [21]

Answer:

899752.13598 N

Explanation:

p = Pressure on the plate = 7.16\times 10^4\ Pa

A = Area = \pi r^2=\pi 2^2=\pi 4

F = Force on the region

When force is divided by area we get pressure

p=\frac{F}{A}\\\Rightarrow F=p\times A\\\Rightarrow F=7.16\times 10^4\times \pi 4\\\Rightarrow F=899752.13598\ N

Force is exerted by the atmosphere on a disk-shaped region is 899752.13598 N

6 0
3 years ago
Learning Goal: To practice Problem-Solving Strategy 7.2 Problems Using Mechanical Energy II. The Great Sandini is a 60.0-kg circ
andreev551 [17]

Answer:

v = 15.8 m/s

Explanation:

Let's analyze the situation a little, we have a compressed spring so it has an elastic energy that will become part kinetic energy and a potential part for the man to get out of the barrel, in addition there is a friction force that they perform work against the movement.  So the variation of mechanical energy is equal to the work of the fictional force

    W_{fr} = ΔEm = Em_{f} -Em₀

Let's write the mechanical energy at each point

Initial

    Em₀ = Ke = ½ k x²

Final

   Em_{f} = K + U = ½ m v² + mg y

Let's use Hooke's law to find compression

    F = - k x

    x = -F / k

    x = 4400/1100

    x = - 4 m

Let's write the energy equation

    fr d = ½ m v² + mgy - ½ k x²

Let's clear the speed

   v² = (fr d + ½ kx² - mg y) 2 / m

   v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50)   2/60.0

   v² = (160 + 8800 - 1470) / 30

   v = √ (229.66)

   v = 15.8 m/s

5 0
4 years ago
Read 2 more answers
What feature on the periodic table separates the metals and non metals?
sertanlavr [38]
Answer: the amphoteric line, mental- nonmetal line, metalloid line, staircase, semimetal line. it can be called any of these names
7 0
3 years ago
In a power plant, pipes transporting superheated vapor are very common. Superheated vapor flows at a rate of 0.3 kg/s inside a p
grigory [225]

Answer:h=160.84 W/m^2-K

Explanation:

Given

mass flow rate=0.3 kg/s

diameter of pipe=5 cm

length of pipe=10 m

Inside temperature=22

Pipe surface =100

Temperature drop=30

specific heat of vapor(c)=2190 J/kg.k

heat supplied Q=mc\Delta T=0.3\times 2190\times (30)

Heat due to convection =hA(100-30)

A=\pi d\cdot L

A=\pi 0.05\times 10=1.571 m^2

Q_{convection}=h\times 1.571\times (100-22)=122.538 h

Q=Q_{convection}

19,710=122.538 h

h=160.84 W/m^2-K

5 0
3 years ago
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