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Difference between object distance and image distance within 4 points .(class 10)

Sergio039 [100]

The relationship between object distance, image distance, and focal length of a spherical mirror is given by

1/f=1/v+1/u

Where

f= focal length of a spherical mirror (distance between the pole and the principal focus of the mirror)

u= object distance (distance between pole and object)

v= image distance (the distance between pole and image)

6 0

3 years ago

Mr. F has taken in a lot of fluid and put out very little. During this period his heart rate has increased a little and his bloo

mezya [45]

Answer:

D

Explanation:

What can be infer from Mr. F situation is that his body is raising blood pressure by both increasing blood volume with all this fluid intake and increasing heart rate. Something may be wrong with his blood volume.

4 0

3 years ago

Convert:<br> 1) 2kg into gram<br> 2) 5200m into km<br> 3) 20cm into m

aivan3 [116]

1) 2 kilograms converted into grams is 2000

2) 5200 meters converted into kilometers is 5.2

3) 20 centimeters converted into meters is 0.2

8 0

3 years ago

A convex, or converging, lens with a focal length of 34 cm is used to observe an image of an apple than is 80 cm away from the l

Hatshy [7]

The image distance is 59.2 cm and the image is real and small.

<h3>Image distance</h3>

The distance of the image formed by the convex or converging lens is determined by applying the following lens equation.

1/f = 1/u + 1/v

where;

f is the focal length = 34 cm
u is the object distance = 80 cm
v is the image distance = ?

1/v = 1/f - 1/u

1/v = 1/34 - 1/80

1/v = 0.0294 - 0.0125

1/v = 0.0169

v = 1/0.0169

v = 59.2 cm

Thus, the image distance is 59.2 cm and the image is real and small.

Learn more about convex lens here: brainly.com/question/10153605

8 0

2 years ago

Two children, Ferdinand and Isabella, are playing with a waterhose on a sunny summer day. Isabella is holding the hose in herhan

sweet [91]

Answer:

84.196%

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

$y_0=1\ m$

x = 10 m

t = Time taken

$v_0$ = 3.5 m/s (assumed, as it is not given)

$A_0$ = $\pi 1.5^2$

We have the equation

$y=y_0+ut+\dfrac{1}{2}gt^2\\\Rightarrow 0=y_0-\dfrac{1}{2}gt^2\\\Rightarrow t=\sqrt{\dfrac{2y_0}{g}}\\\Rightarrow t=\sqrt{\dfrac{2\times 1}{9.81}}\\\Rightarrow t=0.45152\ s$

$x=x_0+vt\\\Rightarrow 10=0+v0.45152\\\Rightarrow v=\dfrac{10}{0.45152}\\\Rightarrow v=22.14741\ m/s$

From continuity equation we have

$Av=A_0v_0\\\Rightarrow A=\dfrac{A_0v_0}{v}\\\Rightarrow A=\dfrac{\pi 1.5^2\times 3.5}{22.14741}\\\Rightarrow A=1.11706\ cm^2$

Fraction is given by

$f=\dfrac{A_0-A}{A_0}\times 100\\\Rightarrow f=\dfrac{\pi 1.5^2-1.11706}{\pi 1.5^2}\times 100\\\Rightarrow f=84.196\ \%$

The fraction is 84.196%

4 0

3 years ago