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Ray Of Light [21]

3 years ago

6

83. A racquet ball is struck in such a way that it leaves the

1 answer:

Readme [11.4K]3 years ago

8 0

Answer:

0.7864m

Explanation:

Ignore air resistance (the ball's horizontal speed stays constant), the time it takes for the ball to travel 1.95 m horizontally at the rate of 4.87 m/s.

t = 1.95 / 4.88 = 0.4s

This is also the time it takes to fall vertically with gravitational acceleration of g = 9.81 m/s2. We can use the following equation of motion to estimate the vertical distance:

$h = gt^2/2$

$h = 9.81*0.4^2/2 = 0.7864 m$

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Why is it important to keep the muzzle of a firearm pointed in a safe direction, even though the firearm's safety is engaged?

Gnom [1K]

The correct answer is B. The safety only prevents you from pulling the trigger, but does not stop the pin from striking the primer. For example, if you drop the firearm, the pin may hit the primer and fire the firearm. It is always responsible to keep the firearm pointed in a safe direction so that if this happens, no consequences come out of it.

6 0

3 years ago

A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the ca

Leona [35]

Answer:

Final speed, v = 28.81 m/s

Explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

$F=ma$

$a=\dfrac{F}{m}$

$a=\dfrac{901}{1423}$

$a=0.63\ m/s^2$

Let v is the final speed of the car. Using third equation of motion to find it as :

$v^2-u^2=2ad$

$v^2=2ad+u^2$

$v^2=2\times 0.63\times 106+(26.4)^2$

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.

5 0

4 years ago

True or false nodes and antinodes occur in longitudinal waves

Vlad [161]

I believe it is false because longitudinal waves travel parallel to the vibration

8 0

3 years ago

You are at the park with your little brother, when you notice a small merry-go-round with a radius that looks to be about 1.5 m.

Elodia [21]

Answer:

Explanation:

angle covered in one rotation = 2π radian

θ = ωt + 1/2 αt²

θ is angle rotated in time t with initial angular velocity of ω and angular acceleration α .

Putting the values

2π = 0 + 1/2 x α x 3²

α = 1. 4 radian / s²

linear acceleration = α x r = 1.4 x 1.5 = 2.1 m / s².

Initial acceleration = 2.1 m /s²

final angular velocity = α t = 1.4 x 3 = 4.2 radian / s

linear velocity = 4.2 x 1.5 = 6.3 m /s

centripetal acceleration = v² / R = 6.3² / 1.5 = 26.46 m /s²

radian acceleration = 26.46 m /s

tangential acceleration = 2.1 m /s²

Total final acceleration = √ ( 26.46² + 2.1² )

= √ ( 700.13 + 4.41)

Final acceleration = 26.53 m / s²

7 0

3 years ago

A student wanted to investigate whether or not the temperature of the water would affect the solubility of sugar. She had three

erastova [34]

ind variable ... temp

dep variable .... amount of sugar dissolved

5 0

3 years ago