Answer:
The first one is x = 9
5 (x + 7) - 3 (x - 4) = 7x + 2
The second one is x = 15
(5x - 9) = 2(x + 6)
The third one is x = -8
4 (3x + 5) - 3 = 9x - 7
(y-k)²/a² + (x-h)²/b² = 1
Vertices being : A(0,1) & B(0, - 9), means that h=0
Let's calculate k: Af₁ + Af₂ = |2+8| = 2a = 10 → a=5 (f₁ and f₂ = focii)
1) a = 10 (WRONG) since a =5
2) h=3 (WRONG) since h =0
3) k =0 (WRONG) since k =5
4) b = 4 RIGHT; PROOF:
we know that : c² = a² - b²
c= 3 & a = 5 then → 3² = 5² - b²
9 = 25 - b²
b² = 25-9 = 16 and b = 4
Answer:
Step-by-step explanation:
These both are independent events. Neither is really a conditional probability. It's like asking "What the chances of getting a heads given that you got a tails in the previous through?" The answer is 1/2 if it is a fair coin.
So the total number of M and Ms is
21+ 15 + 10 + 14 + 5 = 65
5/65 * 14/64 = 0.0168 Be careful you you put that in your calculator.
Part B is a bit harder.
14/65 * 13/64 = 0.04375
Answer:
<u>(1-sinA) * Sin²A</u>
(1+cosA) * Cos²A
<u>(1-sinA) * (1-Cos²A)</u>
(1+cosA) * (1-Sin²A)
<u>(1-sinA) * (1-CosA)(1+CosA)</u>
(1+cosA) * (1-SinA) (1+SinA)
<u>(1-CosA)</u>
(1+SinA)
proved