Question

I will pick the brainiest answer! Thanks! :)

Answer 1

Answer:

$Section \: A. \\before \: the \: donation \ : jane \: had \: \boxed{18 \: (stuffed \: animals)} \\ Section B.\\\boxed{the\: percentage\: of\: female\: student\: is\: \boxed{48 \%}}$

Step-by-step explanation:

$Section A.\\let \: the \: total \: animals \: be \to \: t_{a} \\ let \: the \: donated\: animals \: be \to \: d_{a} \\ then \to \\ if \: d_{a} = \frac{2}{3} (t_{a} ) : we \: can \: find \: t_{a} \: by \to \\ 12 = \frac{2}{3} (t_{a} ) \\ 2(t_{a} )= 12 \times 3 \\ t_{a} = \frac{36}{2} \\ \boxed{ t_{a} = 18.}\\ \\Section B.\\let \: the \: total \: number\: of \: students\: be \: be \to \: t_{s} \\ let \: the \: number\: of \: male\: student\: be \: be \to \: m_{s} \\ then \to \\ if \: t_{s} = m_{s} +1 3 \: then \\m_{s} = t_{s} -13\\m_{s} = 25-13 \\m_{s} =12 \\hence \: percentage \: of \: girls \: is = \frac{12}{25} \times 100 \\the \: percentage\: is \to \boxed{m_{s} = 48\%}$

♨Rage♨

Answer 2

Answer:

The first one: if 2/3 is 12 then 1/3 is 6. 3/3 is 18. SO Jane had 18 stuffed animals  before the donation.

The second one: 25 students then 13 are men so 25-13 is 12. 12/25 as a percentage is 48%

Hope this helps!