All categories

3 years ago

I will pick the brainiest answer! Thanks! :)

Mathematics

2 answers:

Alex_Xolod [135]3 years ago

8 0

Answer:

$Section \: A. \\before \: the \: donation \ : jane \: had \: \boxed{18 \: (stuffed \: animals)} \\ Section B.\\\boxed{the\: percentage\: of\: female\: student\: is\: \boxed{48 \%}}$

Step-by-step explanation:

$Section A.\\let \: the \: total \: animals \: be \to \: t_{a} \\ let \: the \: donated\: animals \: be \to \: d_{a} \\ then \to \\ if \: d_{a} = \frac{2}{3} (t_{a} ) : we \: can \: find \: t_{a} \: by \to \\ 12 = \frac{2}{3} (t_{a} ) \\ 2(t_{a} )= 12 \times 3 \\ t_{a} = \frac{36}{2} \\ \boxed{ t_{a} = 18.}\\ \\Section B.\\let \: the \: total \: number\: of \: students\: be \: be \to \: t_{s} \\ let \: the \: number\: of \: male\: student\: be \: be \to \: m_{s} \\ then \to \\ if \: t_{s} = m_{s} +1 3 \: then \\m_{s} = t_{s} -13\\m_{s} = 25-13 \\m_{s} =12 \\hence \: percentage \: of \: girls \: is = \frac{12}{25} \times 100 \\the \: percentage\: is \to \boxed{m_{s} = 48\%}$

♨Rage♨

umka21 [38]3 years ago

7 0

Answer:

The first one: if 2/3 is 12 then 1/3 is 6. 3/3 is 18. SO Jane had 18 stuffed animals before the donation.

The second one: 25 students then 13 are men so 25-13 is 12. 12/25 as a percentage is 48%

Hope this helps!

You might be interested in

The following table shows the possible meal combinations when choosing an entrée and a side dish at Marty's Diner. Side Dish Ent

Dimas [21]

Answer:

5/9

Step-by-step explanation:

There are 9 total combinations and 3 of them include a burger, 2 of them that have salad but not a burger. If you add them together it equals 5/9

6 0

4 years ago

y eggs in a basket. One quarter of the eggs are sold and four got broken. How many eggs are in the basket in term of y.

elixir [45]

1/4y-4 , hope this helps

3 0

3 years ago

Read 2 more answers

Graph this function:<br> y = 3x + 4

Zinaida [17]

Answer:

(0,−4)

Step-by-step explanation:

6 0

3 years ago

James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo

Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is $y = 2 ^n$

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒ n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒ for n = 1 , y = 2 ..... (1)

Similarly, if the paper if folded TWICE ⇒ n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒ for n = 2 , y = 4 ..... (2)

⇒ $y = 2^2 = 2^n$

Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7

So, $y = 2^ n = 2^7 = 128$

⇒ There are total 128 equal parts.

Lastly, if the paper is folded ELEVEN times ⇒ n = 11

So, $y = 2^ n = 2^{11} = 2048$

⇒ There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is $y = 2 ^n$

8 0

4 years ago

A diagram of a lot of land the scale on the diagram is 1 cm represents 2.5 yards what is the area of the actual lot of land

netineya [11]

In order to determine the area of the lot of land in squared yards, proceed as follow:

Convert the dimensions of the rectangle to yards, by using the given conversion factor:

$\begin{gathered} 7\operatorname{cm}\cdot\frac{2.5yd}{1\operatorname{cm}}=17.5yd \\ 15\operatorname{cm}\cdot\frac{2.5yd}{1\operatorname{cm}}=37.5yd \end{gathered}$

Next, consider that the area of the lot is the area of a rectangle. Replace the previous values of the length and the width of the rectangle:

$A=(17.5yd)(37.5yd)=656.25yd^2$

Hence, the area of the lot of land is 656.25 sq yd

5 0

2 years ago