The rates of 6/23 and 318/811 for the age groups gives a confidence
interval for the difference snoring rate
<h3>What method is used to calculate the confidence interval for the difference in rate?</h3>
The number of younger age group, n₁ = 48 + 136 = 184
Proportion of the younger adult that snored, = 48 ÷ 184 =
The number of older age group, n₂ = 318 + 493 = 811
Proportion of the older adult that snored, = 318 ÷ 811 =
The confidence interval, CI, for the difference in two rate (proportion) is
given as follows;
The z-score at 96% confidence level is 2.05, which gives;
Which gives;
Minimum value in the interval ≈ -0.206
Interval maximum value ≈ -0.056
The confidence interval for the different in the snoring rates between the younger and the older age is therefore;
CI = (-0.206, -0.056) =
Learn more about the finding the confidence interval for the mean of a sample here:
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