Answer:
No
Step-by-step explanation:
Complex answer: For a point to be in quadrant II, it must have a negative x value and a positive y value.
Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't
Are you trying to solve for c? if so c=8
Okay so start with multiplying 93 * 7
So 3 x 7= 21
9 X 7 +63, carry the 2 = 651
Then 8 x 93
Remember that first is a zero.
8 X 3= 24
8 X 9= 72, carry the 2= 74
So that is 7440
Now
0651
+7440
8091
And that's the answer
9.) The relation can not be a function only if the domain is the same. If you plot the points on a graph and use the Vertical Line Test(VLT) you would see that none of the points would be on the same line. It doesn't matter if the range is the same
10.)On the graph your y-intercept would be 2 so that is where you plot your first point. In order to find the slope you need to go up three spaces and one space to the left this is also known as "rise over run". *Remember you always go up spaces for "rise over run" but if the slope is positive then you go to the right and if its negative you go to the left.
I hope this helps love! :)
Five hundred six thousand seven hundred nine.
