I need help on this question

Mathematics

1 answer:

viktelen [127]3 years ago

4 0

start by distributing the exponents outside the parenthesis. we would get:

(3^4)(m^-4)(n^8) / (2^3)(m^-6)(n^3)

first let's apply the exponents to the numbers (3 & 2) to get

81(m^-4)(n^8) / 8(m^-6)(n^3)

note that negative exponents are just flipped positive to the opposite side of the fraction. so (m^-4) in the numerator becomes (m^4) in the denominator. apply this and we get

81(m^6)(n^8) / 8(m^4)(n^3)

after we can simplify to reach

81(m^2)(n^5) / 8

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