Apply quotient rule and chain rule and power rule.

Differentiate both sides with respect to x

You'll get

$\frac{2x(x + y) - x^2(1 + y')}{(x+y)^2} = 2yy'\\\\ \frac{2x^2 + 2xy - x^2+ x^2y'}{(x+y)^2} = 2yy'\\\\2x^2 + 2xy - x^2- x^2y' = 2yy'(x+y)^2\\\\ x^2 + 2xy = 2yy'(x+y)^2 + x^2y'\\\\ x^2 + 2xy = y'(2y(x+y)^2 + x^2)\\\\ y' = \boxed{\bf{\frac{x^2 + 2xy}{2y(x+y)^2 + x^2}}}$

5 0

3 years ago

20.5 meters to 35.5 meters

Ghella [55]

The answer to this question <span> 67.7465%</span>

4 0

3 years ago

WILL MARK YOU BRAINLIEST!!!!!!

My name is Ann [436]

Answer:

y = 88

Step-by-step explanation:

Don't worry about the other stuff, just worry about what's in the triangle that has Y.

53°, 39°, and y°

the sum should be equal to 180 so add 53 adn 39 and subtract it from 180.

180 - (53 + 39) = y

180 - 92 = y

88 = y

Hope this helped! Pls Brainliest my answer! It would help amd mean a lot! ;)

6 0

3 years ago