Answer:
x = 66
Step-by-step explanation:
For a set of N numbers:
{x₁, x₂, ..., xₙ}
The mean can be calculated as:

In this case we have the data set:
{98, 122, 104, 115, 107, x}
And I assume that we want to have the mean = 102.
So we have a set of 6 numbers, the mean of this set will be:

We need to solve this equation for x.
If we multiply both sides by 6, we get:
(98 + 122 + 104 + 115 + 107 + x) = 102*6 = 612
546 + x = 612
x = 612 - 546 = 66
x = 66
Answer:
An irrational number is a real number that can't be written as a fraction.
Ex. 
A rational number is a real number such as a whole number, fraaction, decimal, or integer.
Answer:
338.4Step-by-step explanation:
If you do 80 percent of 188, its 150.4. Then, you add 150.4 to 188. thats 338.4
Answer:
29,900 dollars a year
Step-by-step explanation:
So first we need to find how many weeks are in a year which there are 52.143 weeks but that can be rounded to 52. Now that we know that there are 52 weeks in a year all we have to do is multiply 52 by 575 which equals 29,900 dollars a year.
Hope this helps!
The correct answer is 2.8 liters
Explanation:
The volume of the water in the bottle can be calculated by subtracting 3.5 liters from the volume of water the pail can hold (6.3 liters) because the volume in the bottle is 3.5 liters less than the one in the pail. Below, you can find the process.
volume in the pail - 3.5 liters = volume in the bottle
6.3 liters - 3.5 liters = 2.8 liters
This means the volume of water in the bottle is 2.8 liters. Also, you can double-check this answer by adding the volume in the bottle and the 3.5 liters (2.8 + 3.5 = 6.3).