So in the proper form, the equation would by y = 3x + 15. This means it has a slope of 3. Perpendicular lines have slopes that are negative reciprocals. The negative reciprocal of 3 (or 3/1) is -1/3.
Answer:
going to hell
Step-by-step explanation:
Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
I only know of 4 ways, and this might not even be correct, but here they are.
The first is verbally (a description of words) second is numerically ( by a table of values) third is visually (Graph) last is algebraically ( by a formula)
5/8 = 3/4+1/16 is false because, the final values compared on each side of equation is not the same
- 5/8 = 0.625
- 3/4+1/16 = 0.8125
0.625 = 0.8125, it is not equal but less than
