Answer:
The line '10x-8=10' should be '10x-8=4x+10'
He took 2x away on the right side , as opposed to adding it.
Answer:
Step-by-step explanation:
![\sf = 49y^2+42y+9\\\\=(7y)^2+2(7y)(3)+(3)^2\\\\Using \ Formula \ a^2+2ab+b^2 = (a+b)^2\\\\= (7y+3)^2\\\\= (7y+3)(7y+3)\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%3D%2049y%5E2%2B42y%2B9%5C%5C%5C%5C%3D%287y%29%5E2%2B2%287y%29%283%29%2B%283%29%5E2%5C%5C%5C%5CUsing%20%5C%20Formula%20%5C%20a%5E2%2B2ab%2Bb%5E2%20%3D%20%28a%2Bb%29%5E2%5C%5C%5C%5C%3D%20%287y%2B3%29%5E2%5C%5C%5C%5C%3D%20%287y%2B3%29%287y%2B3%29%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Option d) 115 degrees
Step-by-step explanation:
We are given a trapezium ABDE in the picture. AB and ED are the parallel sides.
F is the mid point of AE and C the midpoint of BD. FC is joined.
We are also given that angle of AED = 65 degrees.
To find the measure of angle BAE.
Since sides AB and ED are parallel sides we find that AE is the transvesal intersecting the two parallel lines.
Hence by parallel lines axiom, the two interior angles namely Angle AED and BAE are supplementary.
i.e. 65 +angle BAE=180
Hence angle BAE = 115 degrees.
Option d is the answer.
The nearest tenth is
129.6
The correct answer would be
A) 80 because if we organize all the tests scores from smallest numbers to biggest, and cross out numbers from each side, and keep going till one is left, we see 80 is the last number in the middle. *below is a image of my work.
