total no. of letters = 11
millimicron
dissecting will give us:
no. of m = 2, no. of i = 3, no. of l = 2, no. of c = 1, no.
of n =1, no. of r = 1, no. of o = 1
we are going to compute this by using permutation
total no. of ways to arrangement = 11!/ [ 2!* 3! * 2! * 1!
*1! *1! *1!]
= 39,916,800/ 24
= 1,663,200 is the answer
Answer:
21 + 25i√3
Step-by-step explanation:
⇒ equation: (p√−3)+q
⇒ p = 25
⇒ q = 21
<em>Plug in:</em>
((25)√−3) + 21
√−3 = i√3
25i√3 + 21
I will leave out the base, b since it's the same for all these logarithms.
The circumference is usually three times as much as the diameter
Answer:
1110
Step-by-step explanation:
