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zaharov [31]
2 years ago
7

Log base 32 of 2 Help

Mathematics
1 answer:
blagie [28]2 years ago
4 0

Answer:

log_{32}(2)=0.2

Step-by-step explanation:

Recall that the unknown (x) here is the log base 32 of 2, so we can write this as the equation:

log_{32}(2)=x

The above equation can be solved by the "change of base formula":

x=\frac{log(2)}{log(32)} \\x=0.2

We can also answer this by trying to solve the exponential equation:

32^x=2

Where we are asked what is the exponent (x) at which we need to raise the base (32) in order to obtain the answer "2"?

Notice that since

2^5=32

Then 32^{1/5} = 2

And 1/5 = 0.2 which also agrees with our previous answer

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428 is greater to or less or equal to 3 hundred 12 tens 8 ones
VLD [36.1K]

Answer:

428 is equal to 428  

Step-by-step explanation:

300 + 120 = 420 + 8 = 428

6 0
3 years ago
Reduce 22/30 to lowest terms and write the numerator in the blank
Zielflug [23.3K]

Answer:

11/15

Step-by-step explanation:

22/30 = 11/15 because they both have a common factor of 2 in the numerator and denominator.

4 0
3 years ago
Can you please help me with the questions I will give you brainliest.
KiRa [710]

Answer:

C the First page

Step-by-step explanation:

1) you input the 2 into the T So the equation would look like this

15+2.5*(times) 2

2) I'm not sure for the second

3) A because you are using the number given then multiplying.

1.58* times 5 = 7.5

But the starting number would be 1.5 sense that's  the first number given

No one report me please.

8 0
3 years ago
Can't seem to figure out this problem. Can anyone help?
Juli2301 [7.4K]
 the third fifth and first

8 0
3 years ago
5
LekaFEV [45]

Answer: y-1=\dfrac32(x+3)

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = \dfrac{d-b}{c-a}

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)

Required equation: y-1=\dfrac32(x+3)

8 0
3 years ago
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