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Art [367]
3 years ago
14

Which inequality is true?

Mathematics
1 answer:
vovangra [49]3 years ago
3 0

Answer:

D |-11 | >-25

Step-by-step explanation:

|-11 | = 11

11 > -25

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If the graph of the function y = x2 is reflected across the x-axis, what equation would correctly describe the new function
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To graph the absolute value graph the function y=f(x). Anything above the x- axis, stays above it.
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Every 1/2 hour Naomi stretches her neck;every 1/3 hour we stretches her legs and every 1/6 hour she stretches her arms. Which pa
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Answer:

She will have stretched her neck 1 time, she will have stretched her legs 2 times, and she will have stretched her arms 4 times.

Step-by-step explanation:

This is because 1/2 can only go into 2/3 once, 1/3 can go into 2/3 twice, and 1/6 can go into 2/3 four times.

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Which polynomials are prime? Check all that apply.
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15x2+10x-9x+7
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50 points! help me! Real answers PLEASE!
Alika [10]

Step-by-step explanation:

Your previous questions answer is

v=23

w=19

x=22

y=26

z=20

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Shawna invests $5,048 in a savings account with a fixed annual interest rate of 4% compounded 12 times per year. How long will i
Elena-2011 [213]

Answer:

5 years

Step-by-step explanation:

In the question we are given;

  • Amount invested or principal amount as $5048
  • Rate of interest as 4% compounded 12 times per year
  • Amount accrued as $6,163.59

We are required to determine the time taken for the money invested to accrue to the given amount;

Using compound interest formula;

A=P(1+\frac{r}{100})^n

where n is the interest period and r is the rate of interest, in this case, 4/12%(0.33%)

Therefore;

6,163.59=5,048(1+\frac{0.333}{100})^n

1.221=(1+\frac{0.333}{100})^n

1.221=(1.0033)^n

introducing logarithms on both sides;

log1.221=log(1.0033)^n\\n=\frac{log1.221}{log1.0033} \\n=60.61

But, 1 year = 12 interest periods

Therefore;

Number of years = 60.61 ÷ 12

                            = 5.0508

                            = 5 years

Therefore, it will take 5 years for the invested amount to accrue to $6163.59

3 0
3 years ago
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