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3 years ago

What is the surface area for this triangular prism?

Mathematics

1 answer:

Annette [7]3 years ago

3 0

Answer:

405.58

Step-by-step explanation:

hope this helps!

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Andrea had 32 problems to do for mathematics homework over the weekend. She did 1/4 of the problems on Friday night, and on Satu

igor_vitrenko [27]

Answer:

Step-by-step explanation:

Problems at start = 32

-Problems done Friday = ¼ × 32 = <u> 8</u>

Problems still to be done = 24

Andrea had to do 24 problems on Saturday to complete the homework.

6 0

3 years ago

Which of these lists include all possible outcome for drawing a marble from a bag with 2 red,3 green, and 2 blue marbles?

Alisiya [41]

Answer:

Step-by-step explanation:

There are only three possible draws, however, some are more likely.

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4 years ago

A phone company worker needs to know the height of a cell tower, so he decides to use a 2 m pole and shadows cast by the sun, as

olganol [36]

I always found it easiest to draw out the picture

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3 years ago

PLEASE HELP Which line has an x-intercept of -5 and a y-intercept of 3?

anygoal [31]

Answer:

the first answer or a

Step-by-step explanation:

just believe meeeee

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3 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago