8(1-8p) + 8p
8 - 64p + 8p
8 - 56p
8 = 56p
1/7 = p
4x=9y+2
x=(9y+2)/4
11x-8=90+9y+2
11((9y+2)/4)-8=9y+92
(99y+22)/4=9y+100
99y+22=36y+400
63y=378
y=6
x=14
is the question asking for y or x？？or is it asking for angle
Answer:14 hrs and 25 mins
Step-by-step explanation:
<span>The square root of 121 is 11. The square toot of a^6 is a^3. Therefore 121a^6 can be expressed as (11a^3)^2, and 11a^3 is a monomial since it is a single term with nothing added or subtracted to it or from it. So 121a^6 as a squared monomial is (11a^3)^2.</span>
Answer: i believe its a x=2
