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wariber [46]
3 years ago
8

Given ADEF: ARST, find the scale factor

Mathematics
2 answers:
Deffense [45]3 years ago
4 0

Answer:

the scale factor is 3/4

x = 16×3/4 = 12

Step-by-step explanation:

the only side length we have for both triangles is the short left side.

we see that we get ED from SR and need to transform 4 into 3. how do we do that ?

well,

4×f = 3

f = 3/4

that is the scaling factor, as all side lengths in EDF are created by multiplying the corresponding side in SRT by the same scaling factor (3/4).

therefore,

x = EF = ST×f = 16×3/4 = 4×3 = 12

andriy [413]3 years ago
4 0

Answer:

The scale factor is 4/3 and x is 12

Step-by-step explanation:

→ Divide RS by DE

4 ÷ 3 = 4/3

→ Divide the answer by 16

16 ÷ 4/3 = 12

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Picture and info down below!
eimsori [14]
The formula for perimeter is 2L + 2W and the formula for the area is L * W, since we don't know the width we will divide 35:7 = 5 and he the measurement for the width.

Now just add L + W = 12 and multiply by 2 the answer is 24
Or 2 * 7 + 2 * 5 = 24
8 0
4 years ago
If f(x) = 5^x2 - 3 and g(x) = x2 - 4x - 8, find (f - g)(x).
kkurt [141]

Answer:

4x² + 4x + 5

Step-by-step explanation:

Note that (f - g)(x) = f(x) - g(x), thus

f(x) - g(x)

= 5x² - 3 - (x² - 4x - 8 ) ← distribute parenthesis by - 1

= 5x² - 3 - x² + 4x + 8 ← collect like terms

= 4x² + 4x + 5

3 0
3 years ago
A pack of 9 toilet rolls costs £4.23
OleMash [197]
 a)  9 toilet rolls cost $ 4.23
       1 toilet roll costs  $ x

          9x = 4.23 * 1
           x= 4.23 / 9
            x = 0.47
So in first case one toilet roll costs $ 0.47.

b) 4 toilet rolls cost $1.96
    1 toilet roll costs  $ x
     
    4x = 1.96 * 1
     x = 1.96 / 4
     x = 0.49
So in second case one toilet roll costs $ 0.49.

0.47 < 0.49
The toilet roll in first case is cheaper than the toilet roll in second case.

Hope this heps!


8 0
3 years ago
7-x=21. help ????????????
Dmitriy789 [7]
X=-14
do you want an explanation <span />
6 0
3 years ago
Read 2 more answers
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
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