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3 years ago

Who all is transgender? if you are not trans gender then don"t ANSWER!!

Biology

1 answer:

Maru [420]3 years ago

7 0

Are u one..? i have transgender friends i like them i dont discriminate

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What are 10 biotic factors of the desert

vova2212 [387]

BIOTIC FACTORS OF DESERT:
-Cacti
-other plants mesquite
-rattlers
-desert tortoise
-desert rats
-hawks
-peccary
-licasrds

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3 years ago

Select ALL the correct answers.A forest was cleared to build a road. Which two would be the most likely effects on the ecosystem

Kryger [21]

Answer:

Some species will develop adaptations to survive in the deforested land.

Some populations will migrate out of the deforested area.

Explanation:

The deforested land will be able to support large trees eventually in the future, and animals cannot instantly adapt to anything.

Therefore, the most logical answers are populations will migrate to forest lands and species will eventually develop adaptations to help them in the newly deforested land.

I hope this helps! :)

4 0

3 years ago

How can plastics in the ocean impact human health?

Thepotemich [5.8K]

I believe the plastics in the oceans are harmful to ocean organisms and human health when people consume ocean organisms. Each plant and animal play its own role in sustaining the world's largest ecosystem. However, due to the ever-growing waste of humanity, we are gradually upsetting this balance. As a global community, we are unable to effectively implement sustainable habits. We produce a lot garbage, and all that garbage has to end up somewhere.

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3 years ago

Which is a function of nucleic acids?

mash [69]

Answer:

they provide structure

7 0

3 years ago

22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

<em>The calculated </em> $X^2$ <em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>

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2 years ago